HandyJSON的用法 swift

下载地址

https://github.com/alibaba/HandyJSON

文档详尽,请看GitHub里的文档

 

HandyJSON 没人维护

现在都用系统json解析了 https://blog.csdn.net/VoidLuffy/article/details/140049718

 

model需要遵循 HandyJSON 协议,class 类需要实现 init方法,Struct 结构体不需要实现 init方法

1.json 串转 model

复制代码
class BasicTypes: HandyJSON {
    var int: Int = 2
    var doubleOptional: Double?
    var stringImplicitlyUnwrapped: String!

    required init() {}
}

let jsonString = "{\"doubleOptional\":1.1,\"stringImplicitlyUnwrapped\":\"hello\",\"int\":1}"
if let object = BasicTypes.deserialize(from: jsonString) {
    print(object.int)
    print(object.doubleOptional!)
    print(object.stringImplicitlyUnwrapped)
}
复制代码

 

2.json 串转 model 数组

复制代码
class Cat: HandyJSON {
    var name: String?
    var id: String?

    required init() {}
}

let jsonArrayString: String? = "[{\"name\":\"Bob\",\"id\":\"1\"}, {\"name\":\"Lily\",\"id\":\"2\"}, {\"name\":\"Lucy\",\"id\":\"3\"}]"
if let cats = [Cat].deserialize(from: jsonArrayString) {
    cats.forEach({ (cat) in
        // ...
    })
}
复制代码

 

3.字典转 model

var dict = [String: Any]()
dict["doubleOptional"] = 1.1
dict["stringImplicitlyUnwrapped"] = "hello"
dict["int"] = 1
if let object = BasicTypes.deserialize(from: dict) {
    // ...
}

 

4.model 转字典

model 转 json 串

复制代码
class BasicTypes: HandyJSON {
    var int: Int = 2
    var doubleOptional: Double?
    var stringImplicitlyUnwrapped: String!

    required init() {}
}

let object = BasicTypes()
object.int = 1
object.doubleOptional = 1.1
object.stringImplicitlyUnwrapped = “hello"

print(object.toJSON()!) // serialize to dictionary
print(object.toJSONString()!) // serialize to JSON string
print(object.toJSONString(prettyPrint: true)!) // serialize to pretty JSON string
复制代码

 

posted @   黄增松  阅读(549)  评论(0编辑  收藏  举报
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