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完全背包

Posted on 2012-08-12 13:56  皇星客栈--Linux  阅读(167)  评论(0)  编辑  收藏  举报

http://acm.hdu.edu.cn/showproblem.php?pid=1114

View Code 
 1 #include<stdio.h>
 2 
 3 int main( )
 4 {
 5     int cases ;
 6     int f ;
 7     int e ;
 8     int maxVolumn ;
 9     int N ;
10     int i ;
11     int j ;
12     int P[50001] ;
13     int W[10001] ;
14     int record[10001] ;
15     const int INF = 1000000001 ;
16     
17     for( scanf("%d",&cases); cases>0 ; cases-- )
18     {
19         scanf( "%d %d",&e,&f);
20         maxVolumn = f - e ;
21         scanf("%d",&N); 
22         for( i = 0 ; i < N ; i++ )
23         {
24             scanf( "%d %d",&P[i],&W[i] );
25         }
26 
27         for( i = 0 ; i <= maxVolumn ; i++ )
28             record[i] = INF ;
29 
30         record[0] = 0 ;
31         
32         for( i = 0 ; i < N ; i++ )
33             for ( j = W[i] ; j <= maxVolumn ; j++ )
34                 if( record[j] > record[j-W[i]]+P[i] )
35                     record[j] = record[j-W[i]]+P[i];
36 
37     
38         
39         if( record[maxVolumn] == INF )
40             printf("This is impossible.\n");
41         else
42             printf("The minimum amount of money in the piggy-bank is %d.\n",record[maxVolumn]);
43     }
44     return 0;
45 }

 

// 这是ambition神牛的版本
// 初始化为-1

View Code 
 1 #include<stdio.h>
 2 int num[10001],w[500],v[500];
 3 main()
 4 {
 5     int n,m,e,f,t,i,j;
 6     for(scanf("%d",&t);t>0;t--)
 7     {
 8         scanf("%d%d",&e,&f);
 9         m=f-e;
10         for(scanf("%d",&n),i=0;i<n;i++)
11             scanf("%d%d",&v[i],&w[i]);
12         num[0]=0;
13         for(i=1;i<=m;i++)
14             num[i]=-1;
15 
16         for(i=0;i<n;i++)
17         {
18             for(j=w[i];j<=m;j++)
19             {
20                 if(num[j-w[i]]!=-1&&num[j]!=-1)
21                 {if(num[j-w[i]]+v[i]<num[j]) num[j]=num[j-w[i]]+v[i];}
22                 else if(num[j-w[i]]!=-1&&num[j]==-1)
23                 {num[j]=num[j-w[i]]+v[i];}
24             }
25         }
26         if(num[m]!=-1)
27         printf("The minimum amount of money in the piggy-bank is %d.\n",num[m]);
28         else
29             printf("This is impossible.\n");
30     }
31     return 0;
32 }