第三章例3-11

#include<stdio.h>
int main(void)
{
	double value1,value2;
	char op;

	printf("Type in an expression:");
	scanf("%lf%c%lf",&value1,&op,&value2);
	if(op=='+')
	    printf("=%.2f\n",value1+value2);
    else if(op=='-')
	    printf("=%.2f\n",value1-value2);
	else if(op=='*')
		printf("=%.2f\n",value1*value2);
	else if(op=='/')
		if(value2!=0)
			printf("=%.2f\n",value1/value2);
		else
			printf("Divisor can not be 0!\n");
		else printf("Unknowm operator!\n");

		return 0;
}