摘要: public List<List<Integer>> levelOrder(TreeNode root) { List<List<Integer>> res = new ArrayList(); if(root == null) return res; Deque<TreeNode> q = new 阅读全文
posted @ 2022-02-22 23:56 明卿册 阅读(18) 评论(0) 推荐(0) 编辑
摘要: public List<Integer> largestValues(TreeNode root) { List<Integer> list = new ArrayList(); if(root == null) return list; Deque<TreeNode> q = new Linked 阅读全文
posted @ 2022-02-22 23:15 明卿册 阅读(16) 评论(0) 推荐(0) 编辑