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Function Run Fun- 递归+细节处理

Solution1

#include<stdio.h>
#include<iostream>
#include<string.h>
#define inf 0x3f3f3f3f
typedef long long ll;
using namespace std;

int book[25][25][25];
int w(int a,int b,int c)
{
    if(a<=0||b<=0||c<=0)
       return 1;
    else if(a>20||b>20||c>20)
        return w(20,20,20);
    else if(book[a][b][c]!=-1)
        return book[a][b][c];
    else if(a<b&&b<c)
        return book[a][b][c]=w(a,b,c-1)+w(a,b-1,c-1)-w(a,b-1,c);
    else
        return book[a][b][c]=w(a-1,b,c)+w(a-1,b-1,c)+w(a-1,b,c-1)-w(a-1,b-1,c-1);
  //  return book[a][b][c];
}
int main()
{
    int a,b,c;
    while(~scanf("%d %d %d",&a,&b,&c))
    {
        if(a==-1&&b==-1&&c==-1)
            break;
        memset(book,-1,sizeof(book));
        printf("w(%d, %d, %d) = %d\n",a,b,c,w(a,b,c));
    }
    return 0;
}

Solution2

int w(int a,int b,int c)
{
    if(a>=0&&a<=20&&b>=0&&b<=20&&c>=0&&c<=20&&book[a][b][c]!=-1)//防止越界
        return book[a][b][c];
    if(a<=0||b<=0||c<=0)
        return 1;
    else if(a>20||b>20||c>20)
        return w(20,20,20);
    else if(a<b&&b<c)
        return book[a][b][c]=w(a,b,c-1)+w(a,b-1,c-1)-w(a,b-1,c);
    else
        return book[a][b][c]=w(a-1,b,c)+w(a-1,b-1,c)+w(a-1,b,c-1)-w(a-1,b-1,c-1);
}
posted @ 2019-09-10 23:23  抓水母的派大星  阅读(316)  评论(0编辑  收藏  举报