codevs2822
解题思路: tarjan缩点后算出度为0的点有几个,如果只有一个且这个点为爱心天使就行了;
#include<iostream> #include<algorithm> #include<vector> #include<queue> #include<cstdio> #include<cstring> #define maxn 10005 using namespace std; struct node { int x; int y; }a[maxn]; struct Edge { int to; int next; }edge[maxn]; int low[maxn]; int dfn[maxn]; int instack[maxn]; int visit[maxn]; int sccno[maxn]; int outdegree[maxn]; int cnt; int step; int indexx; int scc_cnt; int head[maxn]; vector<int>scc[maxn]; void add(int u,int v) { edge[cnt].next=head[u]; edge[cnt].to=v; head[u]=cnt++; return; } void tarjan(int u) { low[u]=dfn[u]=++step; instack[++indexx]=u; visit[u]=1; for(int i=head[u];i!=-1;i=edge[i].next) { if(!dfn[edge[i].to]) { tarjan(edge[i].to); low[u]=min(low[u],low[edge[i].to]); } else if(visit[edge[i].to]) { low[u]=min(low[u],dfn[edge[i].to]); } } if(low[u]==dfn[u]) { scc_cnt++; scc[scc_cnt].clear(); do { scc[scc_cnt].push_back(instack[indexx]); sccno[instack[indexx]]=scc_cnt; visit[instack[indexx]]=0; indexx--; } while(u!=instack[indexx+1]); } return; } void init() { memset(head,-1,sizeof(head)); cnt=step=indexx=scc_cnt=0; memset(visit,0,sizeof(visit)); memset(low,0,sizeof(low)); memset(dfn,0,sizeof(dfn)); return ; } int main() { int n,m; int x,y; init(); scanf("%d%d",&n,&m); for(int i=1;i<=m;i++) { scanf("%d%d",&a[i].x,&a[i].y); add(a[i].x,a[i].y); } for(int i=1;i<=n;i++) if(!dfn[i]) tarjan(i); for(int i=1;i<=n;i++) { if(sccno[a[i].x]!=sccno[a[i].y]) outdegree[sccno[a[i].x]]++; } int flag=0; int pos; for(int i=1;i<=scc_cnt;i++) { if(outdegree[i]==0) { flag++;pos=i; } } int ans=0; for(int i=1;i<=scc_cnt;i++) { if(scc[i].size()>1) ans++; } cout<<ans<<endl; if(flag==1) { if(scc[pos].size()>1) { sort(scc[pos].begin(),scc[pos].end()); for(int i=0;i<scc[pos].size();i++) cout<<scc[pos][i]<<" "; } else cout<<"-1\n"; } else cout<<"-1\n"; return 0; }