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如何在不同编程语言中获取现在的Unix时间戳(Unix timestamp)?

Java time
JavaScript Math.round(new Date().getTime()/1000)getTime()返回数值的单位是毫秒
Microsoft .NET / C# epoch = (DateTime.Now.ToUniversalTime().Ticks - 621355968000000000) / 10000000
MySQL SELECT unix_timestamp(now())
Perl time
PHP time()
PostgreSQL SELECT extract(epoch FROM now())
Python import time 然后 time.time()
Ruby 获取Unix时间戳:Time.now Time.new
显示Unix时间戳:Time.now.to_i
SQL Server SELECT DATEDIFF(s,'1970-01-01 00:00:00',GETUTCDATE())
Unix/Linux date+%s
VBScript/ASP DateDiff("s","01/01/1970 00:00:00",Now())
其他操作系统
(如果Perl被安装在系统中)
命令行状态:perl -e "print time"

如何在不同编程语言中实现Unix时间戳(Unix timestamp) → 普通时间?

Java String date = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").format(new java.util.Date(Unix timestamp * 1000))
JavaScript var unixTimestamp = new Date(Unix timestamp*1000)然后commonTime = unixTimestamp.toLocaleString()
Linux date -d @Unix timestamp
MySQL from_unixtime(Unix timestamp)
Perl my $time = Unix timestamp然后my($sec,$min,$hour,$day,$month, $year) = (localtime($time))[0,1,2,3,4,5,6]
PHP date('r', Unix timestamp)
PostgreSQL SELECT TIMESTAMP WITH TIME ZONE 'epoch' + Unix timestamp) * INTERVAL '1 second';
Python import time 然后 time.gmtime(Unix timestamp)
Ruby Time.at(Unix timestamp)
SQL Server DATEADD(s,Unix timestamp,'1970-01-01 00:00:00')
VBScript/ASP DateAdd("s",Unix timestamp,"01/01/1970 00:00:00")
其他操作系统
(如果Perl被安装在系统中)
命令行状态:perl -e "print scalar(localtime(Unix timestamp))"

如何在不同编程语言中实现普通时间 → Unix时间戳(Unix timestamp)?

Java long epoch = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").parse("01/01/1970 01:00:00");
JavaScript var commonTime = new Date(Date.UTC(year,month -1,day,hour,minute,second))
MySQL SELECT unix_timestamp(time)
时间格式: YYYY-MM-DD HH:MM:SS 或 YYMMDD 或 YYYYMMDD
Perl use Time::Local 然后my $time = timelocal($sec,$min,$hour,$day,$month,$year);
PHP mktime(hour,minute,second,day,month,year)
PostgreSQL SELECT extract(epoch FROM date('YYYY-MM-DD HH:MM:SS'));
Python import time 然后int(time.mktime(time.strptime('YYYY-MM-DD HH:MM:SS','%Y-%m-%d %H:%M:%S')))
Ruby Time.local(year,month,day,hour,minute,second)
SQL Server SELECT DATEDIFF(s,'1970-01-01 00:00:00',time)
Unix/Linux date +%s -d"Jan 1, 1970 00:00:01"
VBScript/ASP DateDiff("s","01/01/1970 00:00:00",time)
posted on 2012-12-18 23:22  黄聪  阅读(1109)  评论(0编辑  收藏  举报