参考github代码

/*******************************************************************
*《剑指Offer——名企面试官精讲典型编程题》C++代码
*
* htfeng
* 2018.09.14
*
* 面试题6:从尾到头打印链表
* 题目:输入一个链表的头节点,从尾到头反过来打印每个节点的值。
*******************************************************************/

#include<iostream>
#include "include/List.h"
#include<stack>

using namespace std;

// 迭代法
void PrintListReversingly_Iteratively(ListNode* pHead) {
    stack<ListNode*> nodes;

    ListNode* pNode = pHead;
    while (pNode != nullptr) {
        nodes.push(pNode);
        pNode = pNode->m_pNext;
    }
    while (!nodes.empty()) {
        pNode = nodes.top();
        cout << pNode->m_nValue << "\t";
        nodes.pop();
    }
    cout << endl;
}

// 递归法
void PrintListReversingly_Recursively(ListNode* pHead) {
    if (pHead != nullptr) {
        if (pHead->m_pNext != nullptr) {
            PrintListReversingly_Recursively(pHead->m_pNext);
        }
    }
    cout << pHead->m_nValue << "\t";
}

// ====================测试代码====================
void Test(ListNode* pHead)
{
    PrintList(pHead);
    cout << "Reversed:" << endl;
    PrintListReversingly_Iteratively(pHead);
    PrintListReversingly_Recursively(pHead);
    cout << endl;
}

// 1->2->3->4->5
void Test1()
{
    cout << "Test1 begins." << endl;

    ListNode* pNode1 = CreateListNode(1);
    ListNode* pNode2 = CreateListNode(2);
    ListNode* pNode3 = CreateListNode(3);
    ListNode* pNode4 = CreateListNode(4);
    ListNode* pNode5 = CreateListNode(5);

    ConnectListNodes(pNode1, pNode2);
    ConnectListNodes(pNode2, pNode3);
    ConnectListNodes(pNode3, pNode4);
    ConnectListNodes(pNode4, pNode5);

    Test(pNode1);

    DestroyList(pNode1);
}

// 只有一个结点的链表: 1
void Test2()
{
    cout << "\nTest2 begins." << endl;

    ListNode* pNode1 = CreateListNode(1);

    Test(pNode1);

    DestroyList(pNode1);
}

// 空链表
void Test3()
{
    cout << "\nTest3 begins." << endl;

    Test(nullptr);
}

int main() {
    Test1();
    Test2();
    //Test3();
    system("pause");
    return 0;
}
posted on 2018-09-14 11:49  一小白  阅读(111)  评论(0编辑  收藏  举报