[容易]合并排序数组 II

题目来源：http://www.lintcode.com/zh-cn/problem/merge-sorted-array/

C++版 VS2012测试通过

 1 //#include <iostream>
 2 //#include <vector>
 3 //using namespace std;
 4 
 5 class Solution {
 6 public:
 7     /**
 8      * @param A: sorted integer array A which has m elements, 
 9      *           but size of A is m+n
10      * @param B: sorted integer array B which has n elements
11      * @return: void
12      */
13     void mergeSortedArray(int A[], int m, int B[], int n) {
14         // write your code here
15         vector<int> v;
16         int i=0,j=0,k=0;
17         while(i<m && j<n)
18         {
19             if(A[i]<B[j])
20                 v.push_back(A[i++]);
21             else
22                 v.push_back(B[j++]);
23         }
24         while(i<m)
25             v.push_back(A[i++]);
26         while(j<n)
27             v.push_back(B[j++]);
28         vector<int>::iterator it;
29         for(it=v.begin();it<v.end();it++)
30             A[k++]=*it;
31     }
32 };
33 
34 //测试
35 //int main()
36 //{
37 //    Solution s;
38 //
39 //    int a[5]={1,2,4};
40 //    int b[2]={3,5};
41 //    s.mergeSortedArray(a,3,b,2);
42 //    for(int i=0;i<5;i++)
43 //        cout<<a[i]<<" ";
44 //}

Python2.7版 spider测试通过

 1 class Solution:
 2     """
 3     @param A: sorted integer array A which has m elements, 
 4               but size of A is m+n
 5     @param B: sorted integer array B which has n elements
 6     @return: void
 7     """
 8     def mergeSortedArray(self, A, m, B, n):
 9         # write your code here
10         i, j, index = m - 1, n - 1, m + n - 1
11         while i >= 0 and j >= 0:
12             if A[i] > B[j]:
13                 A[index] = A[i]
14                 index, i = index - 1, i - 1
15             else:
16                 A[index] = B[j]
17                 index, j = index - 1, j - 1
18         while i >= 0:
19             A[index] = A[i]
20             index, i = index - 1, i - 1
21         while j >= 0:
22             A[index] = B[j]
23             index, j = index - 1, j - 1
24 
25 #测试
26 #if __name__=="__main__":
27 #    s=Solution()
28 #    a=[1,2,4,0,0]
29 #    b=[3,5]
30 #    s.mergeSortedArray(a,3,b,2)
posted @ 2016-06-23 20:55  Pearl_zju  阅读(140)  评论(0)  编辑  收藏  举报