c++ char*作为函数参数

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#include "stdafx.h" #include <iostream> using namespace std;   bool uc_is_usb(char *devid) {     return strlen(devid) > 3 && devid[0] == 'U' && devid[1] == 'S' && devid[2] == 'B'; } int _tmain(int argc, _TCHAR* argv[]) {     char ausb[5] = "USB_";     if (uc_is_usb(ausb))         std::cout << "hello,world" << std::endl;     system("PAUSE");     return 0; }