两个大数计算

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#include<stdio.h> #include<stdlib.h> #include<string.h> int main() {     char a[10050];     char b[10050];     char sum[10051];     while(scanf("%s",a)!=EOF)     {         int flag =0;         scanf("%s",b);         int lena,lenb;         lena = strlen(a);         lenb = strlen(b);         if(lena<lenb)         {             char tmp[10050];             int tmpn;             for(int i =0;i<lenb;i++)             {                 tmp[i] = b[i];                 b[i] = a[i];                 a[i] = tmp[i];             }             tmpn = lenb;             lenb = lena;             lena = tmpn;         }//将长的数组存在a数组中         if(lena!=lenb)//将两个数组对齐         {             int k =lena-lenb;//补k个零             for(int i =lena-1;i>=k;i--)             {                 b[i]=b[i-k];             }             for(int i =0;i<k;i++)             {                 b[i] ='0';             }         }         for(int i=lena;i>0;i--)         {             if(a[i-1]+b[i-1]-'0'+flag>'9')             {                 sum[i] = a[i-1]+b[i-1]-'0'+flag-10;                 flag =1;             }             else             {                 sum[i] = a[i-1]+b[i-1]-'0'+flag;                 flag = 0;             }         }         if(flag==1)         {             sum[0] = '1';         }         if(sum[0]!=0)         {             printf("%c",sum[0]);         }         for(int i=1;i<=lena;i++)         {                           printf("%c",sum[i]);         }         printf("\n");     }     return 0; }