打印出C# 中float ,double 在内存中的存放形式

            float floatA = 2.2f;
            uint a = BitConverter.ToUInt32(BitConverter.GetBytes(floatA), 0);
            for (int i = 0; i < 32;++i )
            {
                uint temp = 0x80000000 & (a << i);
                if (temp==0)
                {
                    Console.Write("0 ");
                }
                else
                {
                    Console.Write("1 ");
                }
            }

            Console.WriteLine();

            double doubleA = 2.2;
            ulong b = BitConverter.ToUInt64(BitConverter.GetBytes(doubleA), 0);
            for (int i = 0; i < 64; ++i)
            {
                ulong temp = 0x8000000000000000 & (b << i);
                if (temp == 0)
                {
                    Console.Write("0 ");
                }
                else
                {
                    Console.Write("1 ");
                }
            }