hdu 1012

http://acm.hdu.edu.cn/showproblem.php?pid=1012

 

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 25495    Accepted Submission(s): 11313

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

 

Sample Output

n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333

 

 

Source

Greater New York 2000

 

 

Recommend

JGShining

 

 

 

#include<stdio.h>
#include<stdlib.h>

int main()
{
    printf("n e\n");
    printf("- -----------\n");
    printf("0 1\n");
    printf("1 2\n");
    printf("2 2.5\n");
    
    
    double m=2.0,i,j,s=2.5;
    for(i=3,j=3;i<10;i++,j++)
    {
      m*=j;  
      //printf("%.1f\n",m);         
      s=s+1/m;
      printf("%.0f %.9f\n",i,s);
    }
    system("pause");
    return 0;
    
}