SqlServer Function 实例

① sql server function 创建

这里使用一个计算年龄精确到分的function作为一个demo,

create Function [dbo].[fn_GetAge]
(
  @BIRTHDAY DateTime ,
  @MATH_DATEE DateTime
) returns Varchar(20)

Begin
DECLARE 
  @n_minute	  decimal(10,0),
  @n_Hour     decimal(10,0) ,
  @n_Days     decimal(10,0) ,
  @n_Months   decimal(10,0) ,
  @n_Years	  decimal(10,0),
  
  @v_Return Varchar(20)
  
  set @n_Years =datediff(YEAR,@BIRTHDAY,@MATH_DATEE) ;
  set @n_Months = datediff(MONTH,@BIRTHDAY,@MATH_DATEE) ;
  set @n_Days =datediff(DAY,@BIRTHDAY,@MATH_DATEE) ;
  set @n_Hour =datediff(HOUR,@BIRTHDAY,@MATH_DATEE) ;
  set @n_minute = datediff(MINUTE,@BIRTHDAY,@MATH_DATEE) ;
  set @v_Return='0';
  
  IF @n_Years = 0
	BEGIN
		IF @n_Months = 0
		  BEGIN
		    IF @n_Days = 0
				BEGIN
					IF @n_Hour = 0
						BEGIN
							set @v_Return = convert(varchar(20),@n_minute) + '分';
						END
					ELSE
						BEGIN
							set @v_Return = convert(varchar(20),@n_Hour) + '小时';
						END
				END
		    ELSE
				BEGIN
					set @v_Return = convert(varchar(20),@n_Days) + '天';
				END
		  END
		ELSE
			BEGIN
				set @v_Return = convert(varchar(20),@n_Months) + '月';
			END
	END	
  ELSE 
	  BEGIN
		set @v_Return = convert(varchar(20),@n_Years) + '岁';
	  END
  

  Return @v_Return; 
End;


GO

② sql server function 使用

select dbo.fn_GetAge('2012-04-25 03:00:00.000','2012-04-25 06:42:00.000') as 年龄

结果：