import re # . 能够替代任意字符 r= re.findall("a..c","abbcsd") print(r) # ^ 找最前面的 r_1 = re.findall("^a.c","abc dsds asc d adc") print(r_1) # $找最后面的 r_2 = re.findall("a.c$","abc dsds asc d adc") print(r_2) # *匹配0~无穷 r_3 = re.findall("ab*","abbbbbbbccccacc") print(r_3) # +匹配1~无穷 r_4 = re.findall("ab+","abbbbbbbccccacc") print(r_4) # ?值匹配0个或者1个 r_5 = re.findall("ab?","abbbbbbbccccacc") print(r_5) # {}值匹配自定义个,优先取最多的 r_5 = re.findall("ab{2,3}","abbbbbbbccccacc") print(r_5) # 前面的*,+,?等都是贪婪匹配,也就是尽可能匹配,后面加?号使其变成惰性匹配,按最少次数匹配(0次) r_6 = re.findall('abc*?','"abbbbbbbccccacc"') print(r_6)
import re # 字符集[] # 在字符集中括号[]中匹配其中一个 re_1 = re.findall("a[asd]c","adc gg aacdd") print(re_1) # [A-Z] [a-z] [0-9] 能匹配其中的任意 一个 字符 re_2 = re.findall("[a-z]","adc gg aacdd") print(re_2) # 若想匹配全部字符需要加*或者+ re_3 = re.findall("[a-z]*","adc2323 g42634g aa2cdd") re_4 = re.findall("[0-9]+","adc2323 g42634g aa2cdd") print(re_3,re_4) # ^在字符集中为非的意思 re_5 = re.findall("g[^a-z]*","adc2323 g42634g aa2cdd") print(re_5)