javascript 截取url参数

1         var url="http://127.0.0.1:8080/photo/list.jsp?page=2&user=hongchen";
2         var params_arr = url.substr(url.indexOf('?')+1).split("&");
3         var params = new Array();
4         for (var i = params_arr.length - 1; i >= 0; i--) {
5             params[params_arr[i].split("=")[0]] = params_arr[i].split("=")[1];
6         };
7         alert(params["page"]);

 

posted @ 2014-03-12 13:06  浪漫小生  阅读(318)  评论(0编辑  收藏  举报