HDU 2054 A==B?

A == B ?



 

Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
 

 

Input
each test case contains two numbers A and B.
 

 

Output
for each case, if A is equal to B, you should print "YES", or print "NO".
 

 

Sample Input
1 2
2 2
3 3
4 3
 

 

Sample Output
NO
YES
YES
NO
 
 
代码：
 1 #include<cstdio>
 2 #include<cstring>
 3 using namespace std;
 4 
 5 const int maxn=100005;
 6 
 7 int main()
 8 {
 9     //freopen("in.txt","r",stdin);
10     int i;
11     int flag1,flag2;
12     bool key1,key2,key;
13     char a[maxn],b[maxn];
14     while(scanf("%s%s",a,b)!=EOF)
15     {
16         key=true;
17         key2=key1=false;
18         int len1=strlen(a);
19         int len2=strlen(b);
20         for(i=0;i<len1;i++)
21         if(a[i]=='.')
22         {
23             flag1=i;
24             key1=true;
25             break;
26         }
27         for(i=0;i<len2;i++)
28         if(b[i]=='.')
29         {
30             flag2=i;
31             key2=true;
32             break;
33         }
34         //key1,key2标记两个是否有小数点 
35         if(!key1&&!key2)
36         if(strcmp(a,b)!=0)
37         key=false; 
38         //没有小数点直接比较 
39         else if(key1&&!key2)
40         {
41             for(i=0;i<flag1;i++)
42             if(a[i]!=b[i])
43             {
44                 key=false;
45                 break;
46             }
47             if(key)
48             for(i=flag1+1;i<len1;i++)
49             if(a[i]!='0')
50             {
51                 key=false;
52                 break;
53             }
54         } 
55         else if(key2&&!key1)
56         {
57             for(i=0;i<flag2;i++)
58             if(a[i]!=b[i])
59             {
60                 key=false;
61                 break;
62             }
63             if(key)
64             for(i=flag2+1;i<len2;i++)
65             if(b[i]!='0')
66             {
67                 key=false;
68                 break;
69             }
70         }
71         /*两个字符串如果一个有一个没有,先比较整数部位,如果相同,再判断有小数点的
72         字符串小数点后面是否都是0*/ 
73         else
74         {
75             if(len1<len2)
76             {
77                 for(i=len1;i<len2;i++)
78                 a[i]='0';
79                 a[i]='\0';
80             }
81             else if(len2<len1)
82             {
83                 for(i=len2;i<len1;i++)
84                 b[i]='0';
85                 b[i]='\0';
86             }
87             else;
88             if(strcmp(a,b)!=0)
89             key=false;
90         }
91         //如果都有小数点,再较短的字符串后面补零再比较. 
92         if(key)
93         printf("YES\n");
94         else
95         printf("NO\n");
96     }
97     return 0;
98 }

 

 

posted on 2015-07-24 19:55  焰  阅读(145)  评论(0)  编辑  收藏  举报

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