Java解析XMl文件之SAX和DOm方法

如题，这两种方法的jar包都在jdk中，不需要下载。

先来说下目录结构：

首先建一个Peron类封装person.xml的属性；DomParseService和SaxParseService分别为两种解析方法的服务类。最后TestXml为测试类。

Person.xml如下：

<?xml version="1.0" encoding="gbk"?>
<Persons>
    <Person id="1">
        <name>zhangsan</name>
        <sex>男</sex>
        <age>30</age>
    </Person>
    <Person id="2">
        <name>lisi</name>
        <sex>女</sex>
        <age>20</age>
    </Person>
</Persons>

 

 

• SAX方法：

public class SaxParseService extends DefaultHandler {
    private List<Person> mPersons = null;
    private Person mPerson = null;
    private String m_preTag = null;

    public List<Person> getPersons(InputStream xmlStream)
            throws ParserConfigurationException, SAXException, IOException {
        SAXParserFactory factory = SAXParserFactory.newInstance();
        SAXParser parser = factory.newSAXParser();
        SaxParseService handler = new SaxParseService();
        parser.parse(xmlStream, handler);
        return handler.getPersons();
    }

    private List<Person> getPersons() {
        return mPersons;
    }

    @Override
    public void startDocument() throws SAXException {
        mPersons = new ArrayList<Person>();
    }

    @Override
    public void startElement(String uri, String localName, String qName,
            Attributes attributes) throws SAXException {
        if ("Person".equals(qName)) {
            mPerson = new Person();
            mPerson.setId(Integer.parseInt(attributes.getValue(0)));
        }
        m_preTag = qName;
    }

    @Override
    public void endElement(String uri, String localName, String qName)
            throws SAXException {
        if ("Person".equals(qName)) {
            mPersons.add(mPerson);
            mPerson = null;
        }
        m_preTag = null;
    }

    @Override
    public void characters(char[] ch, int start, int length)
            throws SAXException {
        if (m_preTag != null) {
            String content = new String(ch, start, length);
            if ("name".equals(m_preTag)) {
                mPerson.setName(content);
            } else if ("sex".equals(m_preTag)) {
                mPerson.setSex(content);
            } else if ("age".equals(m_preTag)) {
                mPerson.setAge(Integer.parseInt(content));
            }
        }
    }

}

• DOM方法：

public class DomParseService {
    public List<Person> getPersons(InputStream is)
            throws ParserConfigurationException, SAXException, IOException {
        List<Person> mPersons = new ArrayList<Person>();
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document element = builder.parse(is);
        NodeList PersonNodes = element.getElementsByTagName("Person");
        for (int i = 0; i < PersonNodes.getLength(); i++) {
            Element PersonElement = (Element) PersonNodes.item(i);
            Person mPerson = new Person();
            mPerson.setId(Integer.parseInt(PersonElement.getAttribute("id")));
            NodeList ChildNodes = PersonElement.getChildNodes();
            for (int j = 0; j < ChildNodes.getLength(); j++) {
                if (ChildNodes.item(j).getNodeType() == Node.ELEMENT_NODE) {
                    if("name".equals(ChildNodes.item(j).getNodeName())){
                        mPerson.setName(ChildNodes.item(j).getFirstChild().getNodeValue());
                    }else if("sex".equals(ChildNodes.item(j).getNodeName())){
                        mPerson.setSex(ChildNodes.item(j).getFirstChild().getNodeValue());
                    }else if("age".equals(ChildNodes.item(j).getNodeName())){
                        mPerson.setAge(Integer.parseInt(ChildNodes.item(j).getFirstChild().getNodeValue()));
                    }
                }
            }
            mPersons.add(mPerson);
        }
        return mPersons;

    }
}

测试类如下。里面正对SAX和DOM分别写了两个方法：

public class TestXml {

    public static void main(String[] args) {
        SaxParse();
        DomParse();
    }
    public static void DomParse() {
        DomParseService dps=new DomParseService();
        try {
            List<Person> mPersons=dps.getPersons(new FileInputStream(new File("e:/Person.xml")));
            for(Person p:mPersons){
                System.out.println(p.getName());
            }
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (ParserConfigurationException e) {
            e.printStackTrace();
        } catch (SAXException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    public static void SaxParse() {
        SaxParseService sps=new SaxParseService();
        try {
             List<Person> Persons=sps.getPersons(new FileInputStream(new File("e:/Person.xml")));
            for(Person p:Persons){
                System.out.println(p.getName());
            }
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (ParserConfigurationException e) {
            e.printStackTrace();
        } catch (SAXException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

}