1.使用for循环计算1-100的和,除了以3结尾的那些数
package zy; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int sum=0; for (int i = 0; i < 101; i++) { int a=i/10; if(a!=3){ sum+=i; } } System.out.println(+sum); } }
2.使用二重循环输出以下图形
*
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package zy; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub for (int i = 1; i <=4; i++) { for (int j = 1; j <=4-i; j++) { System.out.print(" "); } for (int j = 1; j <=2*i-1; j++) { System.out.print("*"); } System.out.print("\n"); } } }
*****
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*
package zy; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub for (int i = 1; i <=4; i++) { for (int j = 1; j <=5-i; j++) { System.out.print("*"); } System.out.print("\n"); } } }
3.循环输入学生姓名,直到输入‘Q’程序结束
package zy; import java.util.Scanner; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); System.out.println("请输入姓名"); String name=input.next(); while(true){ name=input.next(); if(name.equals("Q")){ System.out.println("结束"); } } } }
4.输入5个学生成绩,求和,当输入不合法的时候,提示输入错误重新输入。
package zy; import java.util.Scanner; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); int sum=0; for (int i = 0; i < 5; i++) { System.out.println("输入成绩"); int a=input.nextInt(); if(a>100||a<0){ System.out.println("重新输入"); a=input.nextInt(); } sum+=a; } System.out.println("成绩总和为"+sum); } }
5.计算 1+1/(1+2) + 1/(1+2+3) +1/(1+2+3+4)+…………+1/(1+2+....+10)
package zy; import java.util.Scanner; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub double sum = 0; double a=0; double b=0; double i=1; while(i<11){ a+=i; b=1.0/a; sum+=b; i++; } System.out.println(+sum); } }
6.产生一个1-99的随机数,猜数字,若大了就提示“大了点”,若小了就提示“小了点”直到猜对为止。
(判断猜的次数,如果1-3次,提示太棒了 如果5-8次 一般般 如果8次以上 太笨了)
package zy; import java.util.Random; import java.util.Scanner; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Random r = new Random(); int x = 1 + r.nextInt(98); Scanner input = new Scanner(System.in); System.out.println("请输入1~99的随机数"); int s = input.nextInt(); int a = 1; while (a >= 1) { if (s > x) { System.out.println("大了点"); int j = input.nextInt(); s = j; a++; } else if (s < x) { System.out.println("小了点"); int j = input.nextInt(); s = j; a++; } else { a++; if (a <= 3) System.out.println("太棒了"); if (a >= 4 || a <= 8) System.out.println("一般般"); if (a > 8) System.out.println("太笨了"); break; } } } }
7.输入一个数,判断是不是质数(只能被1和自身整除的数是质数)
package zy; import java.util.Scanner; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); System.out.println("请输入大于1的数"); int a=input.nextInt(); boolean sizhishu=true; for (int i = 2; i < a-1; i++) { if(a%i==0){ sizhishu=false; break; } } if (sizhishu) { System.out.println("是质数"); } else { System.out.println("不是质数"); } } }
8.求裴波那契数列的第20项是什么。裴波那契数列,1,1,2,3,5,8,13,21……
package zy; public class z6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int a=1; int b=1; int c=0; for (int i = 2; i < 20; i++) { c=a+b; a=b; b=c; } System.out.println("第20项为"+c); } }