ROS多线程订阅问题【转载】

一、传统的多线程发布和订阅程序

我们学习ROS的话题订阅和发布时,都是以一个话题的发布和订阅为基础进行学习的,这里博主以两个话题的发布和订阅进行说明,程序如下:

1.mulit_topic_pub.cpp

//包含ros相关的API头文件
#include "ros/ros.h"
//包含在std_msgs库里的String类型
#include "std_msgs/String.h"
#include <sstream>

int main(int argc, char **argv)
{
	ros::init(argc, argv, "multi_pub");
	ros::NodeHandle n;
	//创建发布者,消息类型为std_msgs::String,队列长度为1
	ros::Publisher chatter_pub = n.advertise<std_msgs::String>("chatter1", 1);
	ros::Publisher pub2 = n.advertise<std_msgs::String>("chatter2", 1);
	ros::Rate loop_rate(10);//10HZ
	int count = 0;
	while (ros::ok())
	{
		std_msgs::String msg;
		std::stringstream ss;
		ss << "hello world " << count;
		msg.data = ss.str();

		std_msgs::String msg2;
		std::stringstream ss2;
		ss2 << "hello " << count;
		msg2.data = ss2.str();

		ROS_INFO("%s", msg.data.c_str());
		ROS_INFO("%s", msg2.data.c_str());

		chatter_pub.publish(msg);
		pub2.publish(msg2);

		ros::spinOnce();

		loop_rate.sleep();
		++count;
	}
	 return 0;
}

2.multi_topic_sub.cpp

#include "ros/ros.h"
#include "std_msgs/String.h"

class multiReceiver
{
public:
	multiReceiver()
	{	
		sub = nh.subscribe("chatter1", 1, &multiReceiver::chatterCallback1,this);
		sub2 = nh.subscribe("chatter2", 1, &multiReceiver::chatterCallback2,this);
	}
	void chatterCallback1(const std_msgs::String::ConstPtr& msg);
	void chatterCallback2(const std_msgs::String::ConstPtr& msg);
private:
	ros::NodeHandle nh;
	ros::Subscriber sub;
	ros::Subscriber sub2;
};


void multiReceiver::chatterCallback1(const std_msgs::String::ConstPtr& msg)
{
  ROS_INFO("I heard: [%s]", msg->data.c_str());
  ros::Rate loop_rate(0.5);//block chatterCallback2()
  loop_rate.sleep();
}

void multiReceiver::chatterCallback2(const std_msgs::String::ConstPtr& msg)
{
  ROS_INFO("I heard: [%s]", msg->data.c_str());
}
  
int main(int argc, char **argv)
{
  ros::init(argc, argv, "multi_sub");
  multiReceiver recOb;
  ros::spin();
  return 0;
}

对于一些只订阅一个话题的简单节点来说,我们使用ros::spin()进入接收循环,每当有订阅的话题发布时,进入回调函数接收和处理消息数据。但是更多的时候,一个节点往往要接收和处理不同来源的数据,并且这些数据的产生频率也各不相同,当我们在一个回调函数里耗费太多时间时,会导致其他回调函数被阻塞,导致数据丢失。这种场合需要给一个节点开辟多个线程,保证数据流的畅通。

以10hz的频率发布了chatter1和chatter2两个话题,在订阅程序中,回调函数1中加入了2s的延时,导致了回调函数2也只能2s才能接收到一个数据,为了是回调函数2能正常接收数据,为此我们要探究以下多线程控制的相关技术。

二、多线程函数介绍

首先,在多线程编程中,有两个常用的多线程函数,分别是ros::MultiThreadedSpinner和ros::AsyncSpinner,他们可以在一个节点中开辟多个线程,这里博主参考的是官方的多线程教程中的相关介绍,链接如下:

链接: [http://wiki.ros.org/roscpp/Overview/Callbacks and Spinning](http://wiki.ros.org/roscpp/Overview/Callbacks and Spinning).

1.ros::MultiThreadedSpinner

ros::MultiThreadedSpinner spinner(4); // Use 4 threads
spinner.spin(); // spin() will not return until the node has been shutdown

2.ros::AsyncSpinner

ros::AsyncSpinner spinner(4); // Use 4 threads
spinner.start();
ros::waitForShutdown();

三、多线程发布和订阅程序

在原有mulit_topic_sub.cpp文件的基础上进行修改,修改如下,multi_thread_sub.cpp文件是根据ros::MultiThreadedSpinner函数进行修改的,multi_thread_sub2.cpp文件是根据ros::AsyncSpinner函数进行修改的

1.mulit_thread_sub.cpp

#include "ros/ros.h"
#include "std_msgs/String.h"
#include <boost/thread.hpp>

class multiThreadListener
{
public:
	multiThreadListener()
	{	
		sub = n.subscribe("chatter1", 1, &multiThreadListener::chatterCallback1,this);
		sub2 = n.subscribe("chatter2", 1, &multiThreadListener::chatterCallback2,this);
	}
	void chatterCallback1(const std_msgs::String::ConstPtr& msg);
	void chatterCallback2(const std_msgs::String::ConstPtr& msg);

private:
	ros::NodeHandle n;
	ros::Subscriber sub;
	ros::Subscriber sub2;
};

void multiThreadListener::chatterCallback1(const std_msgs::String::ConstPtr& msg)
{
  ROS_INFO("I heard: [%s]", msg->data.c_str());
  ros::Rate loop_rate(0.5);//block chatterCallback2()
  loop_rate.sleep();
}

void multiThreadListener::chatterCallback2(const std_msgs::String::ConstPtr& msg)
{
  ROS_INFO("I heard: [%s]", msg->data.c_str());
}
  
int main(int argc, char **argv)
{

  ros::init(argc, argv, "multi_sub");

  multiThreadListener listener_obj;
  ros::MultiThreadedSpinner s(2);
  ros::spin(s);

  return 0;
}

2.mulit_thread_sub2.cpp

#include "ros/ros.h"
#include "std_msgs/String.h"
#include <boost/thread.hpp>

class multiThreadListener
{
public:
	multiThreadListener()
	{	
		sub = n.subscribe("chatter1", 1, &multiThreadListener::chatterCallback1,this);
		sub2 = n.subscribe("chatter2", 1, &multiThreadListener::chatterCallback2,this);
	}
	void chatterCallback1(const std_msgs::String::ConstPtr& msg);
	void chatterCallback2(const std_msgs::String::ConstPtr& msg);

private:
	ros::NodeHandle n;
	ros::Subscriber sub;
	ros::Subscriber sub2;
  
};

void multiThreadListener::chatterCallback1(const std_msgs::String::ConstPtr& msg)
{
  ROS_INFO("I heard: [%s]", msg->data.c_str());
  ros::Rate loop_rate(0.5);//block chatterCallback2()
  loop_rate.sleep();
}

void multiThreadListener::chatterCallback2(const std_msgs::String::ConstPtr& msg)
{
  ROS_INFO("I heard: [%s]", msg->data.c_str());
}
  
int main(int argc, char **argv)
{
  ros::init(argc, argv, "multi_sub");

  multiThreadListener listener_obj;
  
  ros::AsyncSpinner spinner(2); // Use 2 threads
  spinner.start();
  ros::waitForShutdown();

  return 0;
}


代码运行效果一致,可以很清楚的看到,两个订阅者之间并没有相互阻塞,同时完成了对话题的订阅和信息打印

相比较之下,AsyncSpinner比MultiThreadedSpinner更优,它有start() 和stop() 函数,并且在销毁的时候会自动停止,这样我们就完成了ubuntu16.04下多话题订阅和发布的目的了

四、Python中如何解决该问题

在python中测试时,发现并不需要多线程,猜测时rospy应该为每个回调函数自动添加了多线程操作,所以在python中订阅同时订阅多个话题就可以了。可以忽略上文中C++的类似处理。

原文链接:(84条消息) 【ROS】ubuntu16.04下实现多线程话题订阅和发布_亦乐大大的博客-CSDN博客

参考链接:动手学ROS(7):精讲多线程之MultiThreadedSpinner - 知乎 (zhihu.com)

posted @ 2022-07-15 11:04  hiccup_lh  阅读(1501)  评论(0编辑  收藏  举报