SQL-运算符

SELECT 100,100+0,100-0,100+50,100+50*30,100+35.5,100-35.5 FROM DUAL;
SELECT 100*1,100*1.0,100/1.0,100/2,100+2*5/2,100/3,100 DIV 0 FROM DUAL;
SELECT 12%3,12%5,12 MOD -5,-12%5,-12%-5 FROM DUAL;

 

 

 

2.比较运算符

 

 

 

关键字运算符

 

 LIKE与各种符号一起使用

%:表示匹配0或多个

_:下划线表示匹配1个

\:下划线表示转义字符

 

 

 

 

 

 

 

 

 

练习题:

#1.选择工资不在5000到12000的员工的姓名和工资
SELECT last_name,salary FROM employees WHERE salary NOT BETWEEN 5000 AND 12000;
#2.选择在20或50号部门工作的员工姓名和部门号
SELECT last_name,department_id FROM employees WHERE department_id IN (20,50);
#3.选择公司中没有管理者的员工姓名及job_id
SELECT last_name,job_id FROM employees WHERE manager_id IS NULL;
#4.选择公司中有奖金的员工姓名,工资和奖金级别
SELECT last_name,salary,commission_pct FROM employees WHERE commission_pct IS NOT NULL;
#5.选择员工姓名的第三个字母是a的员工姓名
SELECT last_name FROM employees WHERE last_name LIKE '__a%';
#6.选择姓名中有字母a和k的员工姓名
SELECT last_name FROM employees WHERE last_name LIKE '%a%' AND last_name LIKE '%k%';
#7.显示出表employees表中first_name 以'e'结尾的员工信息
SELECT * FROM employees WHERE first_name LIKE '%e';
#8.显示出表出表employees表中部门编号在80-100之间的姓名、工种
SELECT last_name,job_id FROM employees WHERE department_id BETWEEN 80 AND 100;
#9.显示出表employees的manager_id是100,101,110的员工姓名、工资、管理者id
SELECT last_name,salary,manager_id FROM employees WHERE manager_id IN (100,101,110);

  

 

posted @ 2023-02-26 18:42  SiNanhong  阅读(33)  评论(0编辑  收藏  举报