Python-Debug（pycharm中调试细节）

pycharm常用debug按钮：

Show Execution Point(Alt + F10)：跳转到代码执行位置

Step Over（F8）：执行当前代码，但是不会进入函数

Step into（F7）：执行当前代码，会进入函数（包括源码）

Step Into my Code（Alt + shift + F7）：执行当前代码，会进入函数（仅包括自己写的代码）

Step out（shift + F8）：跳出函数体

例子：

玩家输入剪刀石头布与机器人PK，自动输出结果

两个函数，mian执行函数，computer电脑函数，源码如下：

main.py

from computer import Robot,Calculate

if __name__ == '__main__':
    person_put = int(input("请输入1=剪刀, 2=石头, 3=布\n"))
    robot = Robot()
    robot_put = robot.run()
    calculate = Calculate(person_put,robot_put)
    result = calculate.result()
    print("robot is %d, result is %s" %(robot_put,result))

computer.py

import random

class Robot(object):
    def __init__(self):
        self.robot_putlist = [1,2,3] #1=剪刀,2=石头,3=布

    def run(self):
        return random.choice(self.robot_putlist)

class Calculate(object):
    def __init__(self,person_put,robot_put):
        self.person_put = person_put
        self.robot_put = robot_put

    def result(self):
        if (self.person_put == 1 and self.robot_put == 1) or (
                self.person_put == 2 and self.robot_put == 2) or (
                self.person_put == 3 and self.robot_put == 3):
            return "draw"
        elif (self.person_put == 1 and self.robot_put == 2) or (
                self.person_put == 2 and self.robot_put == 3) or (
                self.person_put == 3 and self.robot_put == 1):
            return "lose"
        elif (self.person_put == 1 and self.robot_put == 3) or (
                self.person_put == 2 and self.robot_put == 1) or (
                self.person_put == 3 and self.robot_put == 2):
            return "win"
        else:
            return "null"