jquery ajax 无刷新上传

 

var form = new FormData();
form.append('file', $("#submitmaterials").find("input")[1].files[0]);
$.ajax({
	url: server_url + "scbg/doscbg?ajid" + current_case.ajid + "&accessToken=" + accessToken,
	type: 'POST',
	cache: false,
	data: form,
	processData: false,
	contentType: false,
	success: function (data) {
		if (data == 'error') {

		}
	}
});

  

posted @ 2018-06-06 21:04  GordonDicaprio  阅读(171)  评论(0编辑  收藏  举报