CouncurrentHashMap的源码疑问

最近学习了一下CouncurrentHashMap的源码 突然有个疑问
rehash
void rehash() {
            HashEntry<K,V>[] oldTable = table;
            int oldCapacity = oldTable.length;
            if (oldCapacity >= MAXIMUM_CAPACITY)
                return;

            /*
             * Reclassify nodes in each list to new Map.  Because we are
             * using power-of-two expansion, the elements from each bin
             * must either stay at same index, or move with a power of two
             * offset. We eliminate unnecessary node creation by catching
             * cases where old nodes can be reused because their next
             * fields won't change. Statistically, at the default
             * threshold, only about one-sixth of them need cloning when
             * a table doubles. The nodes they replace will be garbage
             * collectable as soon as they are no longer referenced by any
             * reader thread that may be in the midst of traversing table
             * right now.
             */

            HashEntry<K,V>[] newTable = HashEntry.newArray(oldCapacity<<1);
            threshold = (int)(newTable.length * loadFactor);
            int sizeMask = newTable.length - 1;
            for (int i = 0; i < oldCapacity ; i++) {
                // We need to guarantee that any existing reads of old Map can
                //  proceed. So we cannot yet null out each bin.
                HashEntry<K,V> e = oldTable[i];

                if (e != null) {
                    HashEntry<K,V> next = e.next;
                    int idx = e.hash & sizeMask;

                    //  Single node on list
                    if (next == null)
                        newTable[idx] = e;

                    else {
                        // Reuse trailing consecutive sequence at same slot
                        HashEntry<K,V> lastRun = e;
                        int lastIdx = idx;
                        for (HashEntry<K,V> last = next;
                             last != null;
                             last = last.next) {
                            int k = last.hash & sizeMask;
                            if (k != lastIdx) {
                                lastIdx = k;
                                lastRun = last;
                            }
                        }
                        newTable[lastIdx] = lastRun;

                        // Clone all remaining nodes
                        for (HashEntry<K,V> p = e; p != lastRun; p = p.next) {
                            int k = p.hash & sizeMask;
                            HashEntry<K,V> n = newTable[k];
                            newTable[k] = new HashEntry<K,V>(p.key, p.hash,
                                                             n, p.value);
                        }
                    }
                }
            }
            table = newTable;
        }

我发现在代码执行开始
 HashEntry<K,V>[] oldTable = table; 获取了最新的table（table是volatile的）
代码执行过程并未加锁，那么在高并发环境下，在rehash时势必会丢失一些值，不知道我理解的对不对，哪位高手能详细的解释下。