数字在排序数组中出现的次数
题目:统计一个数字在排序数组中出现的次数。例如输入排序数组{1,2,3,3,3,3,4,5}和数字3,由于3在这个数组中出现了4次,因此输出4.
找到排序数组中的第一个K:
int GetFirstK(int *data, int length, int k, int start, int end) { if(start > end) return -1; int middleIndex = start + ((end - start) >> 1); int middleData = data[middleIndex]; if(middleData == k) { if((middleIndex > 0 && data[middleIndex - 1] != k) || middleIndex == 0) return middleIndex; else end = middleIndex - 1; } else if(middleData > k) end = middleIndex - 1; else start = middleIndex + 1; return GetFirstK(data, length, k, start, end); }
找到排序数组中最后一个k:
int GetLastK(int *data, int length, int k, int start, int end) { if(start > end) return -1; int middleIndex = start + ((end - start) >> 1); int middleData = data[middleIndex]; if(middleData == k) { if((middleIndex < length - 1 && data[middleIndex + 1] != k) || middleIndex == length -1) return middleIndex; else start = middleIndex + 1; } else if(middleData < k) start = middleIndex + 1; else end = middleIndex - 1; return GetLastK(data, length, k, start, end); }
在分别找到第一个k和最后一个k的下标之后,就能计算出k在数组中出现的次数了。相应的代码如下:
int GetNumberOfK(int *data, int length, int k) { int number = 0; if(data != NULL && length > 0) { int first = GetFirstK(data, length, k, 0, length - 1); int last = GetLastK(data, length, k, 0, length - 1); if(first > -1 && last > -1) number = last - first + 1; } return number; }
完整代码如下:
int GetFirstK(int *data, int length, int k, int start, int end) { if(start > end) return -1; int middleIndex = start + ((end - start) >> 1); int middleData = data[middleIndex]; if(middleData == k) { if((middleIndex > 0 && data[middleIndex - 1] != k) || middleIndex == 0) return middleIndex; else end = middleIndex - 1; } else if(middleData > k) end = middleIndex - 1; else start = middleIndex + 1; return GetFirstK(data, length, k, start, end); } int GetLastK(int *data, int length, int k, int start, int end) { if(start > end) return -1; int middleIndex = start + ((end - start) >> 1); int middleData = data[middleIndex]; if(middleData == k) { if((middleIndex < length - 1 && data[middleIndex + 1] != k) || middleIndex == length -1) return middleIndex; else start = middleIndex + 1; } else if(middleData < k) start = middleIndex + 1; else end = middleIndex - 1; return GetLastK(data, length, k, start, end); } int GetNumberOfK(int *data, int length, int k) { int number = 0; if(data != NULL && length > 0) { int first = GetFirstK(data, length, k, 0, length - 1); int last = GetLastK(data, length, k, 0, length - 1); if(first > -1 && last > -1) number = last - first + 1; } return number; }
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