Oracle对树形结构按级次排序SQL
1、自顶向下查找
select t.name, t.id
from tree t
start with t.id = 'top'
CONNECT BY PRIOR t.id = t.parent_id
order SIBLINGS by t.order_no
2、自底向上查找
select t.name, t.id
from tree t
start with t.id = 'top'
CONNECT BY PRIOR t.parent_id = t.id
order SIBLINGS by t.order_no
select t.name, t.id
from tree t
start with t.id = 'top'
CONNECT BY PRIOR t.id = t.parent_id
order SIBLINGS by t.order_no
2、自底向上查找
select t.name, t.id
from tree t
start with t.id = 'top'
CONNECT BY PRIOR t.parent_id = t.id
order SIBLINGS by t.order_no
posted on 2009-10-12 13:47 Hero King 阅读(1465) 评论(0) 编辑 收藏 举报