1：Counter对列表进行计数，找重复
from collections import Counter
a = ["61e7f868eeb03046b96906dd","61e7f861fe380309df61ddf2","61e7f861fe380309df61ddf1",
"61e7f861fe380309df61ddf0","61e7f85b7258f7696c55f72e","61e7f85b7258f7696c55f72d","61e7f861fe380309df61ddf0"
]
b = dict(Counter(a)) #{'61e7f868eeb03046b96906dd': 1, '61e7f861fe380309df61ddf2': 1, '61e7f861fe380309df61ddf1': 1, '61e7f861fe380309df61ddf0': 2, '61e7f85b7258f7696c55f72e': 1, '61e7f85b7258f7696c55f72d': 1}
print(b)
# print ([key for key,value in b.items() if value > 1]) #只展示重复元素
# print ({key:value for key,value in b.items() if value > 1}) #展现重复元素和重复次数
# a = [{'pay_order_no': '164264954668065756', 'is_del': 0}, {'pay_order_no': '164264972082245062', 'is_del': 1}, {'pay_order_no': '164264996092254304', 'is_del': 1}, {'pay_order_no': '164265021689661895', 'is_del': 0}, {'pay_order_no': '164265063783351017', 'is_del': 0}, {'pay_order_no': '164265075567892474', 'is_del': 0}, {'pay_order_no': '164265076330341903', 'is_del': 0}, {'pay_order_no': '164265087134341611', 'is_del': 1}, {'pay_order_no': '164265089388312149', 'is_del': 1}, {'pay_order_no': '164265101568633361', 'is_del': 0}]
2：asq。query
from asq import query
a = [
{
"card_id": 210,
"donate_count": 6,
"id": 210,
"card_name": "这是一张犯人卡",
"card_num": "AAA6",
"card_grade_id": 158,
"card_rarity": 6
},{
"card_id": 210,
"donate_count": 6,
"id": 210,
"card_name": "这是一张犯人卡",
"card_num": "AAA6",
"card_grade_id": 158,
"card_rarity": 6
}, {
"card_id": 210,
"donate_count": 6,
"id": 210,
"card_name": "这是一张犯人卡",
"card_num": "AAA6",
"card_grade_id": 160,
"card_rarity": 6
}
]
a = query(a).group_by(lambda x:x["card_grade_id"]).select(lambda x:[x[0]["card_grade_id"],x.sum(lambda x:x["donate_count"])]).to_list()
print(a) # [158, 12][160, 6]
