摘要: # *_*coding:utf-8_*_ def range2(n): count = 0 while count < n: count = count + 1 sign = yield count # return if sign == 'stop': print(' stop ', sign) 阅读全文
posted @ 2020-12-01 15:46 ty1539 阅读(194) 评论(0) 推荐(0) 编辑