/*
G
Commando War
Input: Standard Input
Output: Standard Output
“Waiting for orders we held in the wood, word from the front never came
By evening the sound of the gunfire was miles away
Ah softly we moved through the shadows, slip away through the trees
Crossing their lines in the mists in the fields on our hands and our knees
And all that I ever, was able to see
The fire in the air, glowing red, silhouetting the smoke on the breeze”
There is a war and it doesn't look very promising for your country. Now it's time to act. You have a commando squad at your disposal and planning an ambush on an important enemy camp located nearby. You have N soldiers in your squad. In your master-plan, every single soldier has a unique responsibility and you don't want any of your soldier to know the plan for other soldiers so that everyone can focus on his task only. In order to enforce this, you brief every individual soldier about his tasks separately and just before sending him to the battlefield. You know that every single soldier needs a certain amount of time to execute his job. You also know very clearly how much time you need to brief every single soldier. Being anxious to finish the total operation as soon as possible, you need to find an order of briefing your soldiers that will minimize the time necessary for all the soldiers to complete their tasks. You may assume that, no soldier has a plan that depends on the tasks of his fellows. In other words, once a soldier begins a task, he can finish it without the necessity of pausing in between.
Input
There will be multiple test cases in the input file. Every test case starts with an integer N (1<=N<=1000), denoting the number of soldiers. Each of the following N lines describe a soldier with two integers B (1<=B<=10000) & J (1<=J<=10000). B seconds are needed to brief the soldier while completing his job needs J seconds. The end of input will be denoted by a case with N =0 . This case should not be processed.
Output
For each test case, print a line in the format, “Case X: Y”, where X is the case number & Y is the total number of seconds counted from the start of your first briefing till the completion of all jobs.
Sample Input Output for Sample Input
3
2 5
3 2
2 1
3
3 3
4 4
5 5
0
Case 1: 8
Case 2: 15
Problem Setter: Mohammad Mahmudur Rahman, Special Thanks: Manzurur Rahman Khan
题意:
指挥官给N个军人分配任务，需用 B[i] 的时间给第i个人陈述任务，
而此人需用 J[i] 的时间去完成此任务。问最短执行完所有任务的总时间。
*/
#include <iostream>
#include<algorithm>
#include<queue>
#include<stack>
#include<cmath>
#include<string.h>
#include<stdio.h>
#include<stdlib.h>
using namespace std;
#define maxn 2600
struct Time
{
int B;
int J;
bool operator < (const Time &a)const
{
return a.J<J;//从大到小排列
}
} ti[maxn];
int sum[maxn];//可以不用数组，表示当时不知道怎么想的
int main()
{
int T,i,ans;
int casen=0;
while(scanf("%d",&T),T)
{
casen++;
ans=0;
memset(sum,0,sizeof(sum));
for(i=0; i<T; i++)
{
scanf("%d%d",&ti[i].B,&ti[i].J);
}
sort(ti,ti+T);
/*for(i=0; i<T; i++)
{
printf("%d %d\n",ti[i].B,ti[i].J);
}*/
sum[0]=ti[0].B;
ans=sum[0]+ti[0].J;
for(i=1; i<T; i++)
{
sum[i]=sum[i-1]+ti[i].B;
// printf(" = %d ans = %d\n",sum[i],ans);
if(sum[i]+ti[i].J>ans)
ans=sum[i]+ti[i].J;
}
printf("Case %d: %d\n",casen,ans);
}
return 0;
}
