ajax请求

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
  <head>
	<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
	<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
  </head>
<body>

	<button type="button" id="buttonid">发送ajax请求</button>
	
	<script>
		$('#buttonid').bind('click', function() {
			$.ajax({
				url : 'YOUR_URL',
				type : 'POST',
				data : {'key1' : 'val1', 'key2' : 'val2'},
				dataType : 'JSON',
				success : function(json) {
					console.log('succ');
				},
				error : function() {
					console.log('error');
				}
			});
		});
	</script>
	
</body>
</html>

  

posted @ 2015-09-10 16:07  helloweworld  阅读(400)  评论(0编辑  收藏  举报