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while(~scanf("%d", &n)) 和 while(scanf("%d", &n), n) 有啥不同

额............我也不知道(先记下)

printf("%d\n", (scanf("%d", &n), n))

printf("%d\n", (~scanf("%d", &n)));

打印结果都相同........

 

测试题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1787

 

测试代码:

代码参考博客:https://blog.csdn.net/ydd97/article/details/47168351

#include <iostream>
#include <vector>
#include <cstdio>
#define ll long long

using namespace std;


ll euler(ll n) {
    int ret = n;
    for (int i = 2; i * i <= n; i++) {
        if (n%i==0) {
            ret -= ret / i;
            while(n%i == 0) {
                n /= i; 
            }
        }
    }
    
    if (n > 1) ret -= ret / n;
    return ret;
}

int main() {
    int n;
//    printf("%lld\n", (scanf("%d", &n), n));
//    printf("%lld\n", (~scanf("%d", &n)));
     while(scanf("%d", &n), n) {
//    while(~scanf("%d", &n)) {
        printf("%d\n", n-euler(n)-1);
    }
    return 0;
}

 

 今天看到一篇博客:

 

 可能也是这样想的。然后就没有然后了

 

posted @ 2020-07-20 22:53  你若愿意,我一定去  阅读(256)  评论(0编辑  收藏  举报
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