5-3 两点间距离计算

给出下面的一个基类框架:

class Point_1D

{ protected:

float x;//1D 点的x坐标

public:

Point_1D(float p = 0.0);

float distance(const Point_1D & p2);

}

以Point_1D为基类建立一个派生类Point_2D,增加一个保护数据成员:

float y;//2D平面上点的y坐标

以Point_2D为直接基类再建立一个派生类Point_3D,增加一个保护数据成员:

float z;//3D立体空间中点的z坐标

生成上述类并编写主函数,根据输入的点的基本信息,建立点对象,并能计算该点到原点的距离。

输入格式: 测试输入包含若干测试用例,每个测试用例占一行(点的类型(1表示1D点,2表示2D点,3表示3D点) 第一个点坐标信息(与点的类型相关) 第二个点坐标信息(与点的类型相关))。当读入0时输入结束,相应的结果不要输出。

输入样例:

1 -1 0

2 3 4 0 0

3 1 2 2 0 0 0

0

输出样例:

Distance from Point -1 to Point 0 is 1

Distance from Point(3,4) to Point(0,0) is 5

Distance from Point(3,3,3) to Point(0,0,0) is 3

参考代码

#include<iostream>
#include<math.h>
using namespace std;
//本题考察多层继承,将数据设为保护类,并使用公有继承 
//建立一维类 
class Point_1D
{  
protected:
    float x;//1D 点的x坐标
public:
    void set_1D(){cin>>x;}
    float distance(const Point_1D & p2);
};
//建立二维类 
class Point_2D:public Point_1D
{
protected:
    float y;//2D平面上点的y坐标
public:
    void set_2D(){set_1D();cin>>y;}//调用基类set方法 
    float distance(const Point_2D & p2);
};
//建立三维类 
class Point_3D:public Point_2D
{
protected:
    float z;//3D立体空间中点的z坐标
public:
    void set_3D(){set_2D();cin>>z;}
    float distance(const Point_3D & p2);
};
int main()
{
    int type;
    Point_1D a1,a2;
    Point_2D b1,b2;
    Point_3D c1,c2;
    cin>>type;
    while(type)
    {
      switch(type)
      {
        case 1:a1.set_1D();a2.set_1D();a1.distance(a2);break;
        case 2:b1.set_2D();b2.set_2D();b1.distance(b2);break;
        case 3:c1.set_3D();c2.set_3D();c1.distance(c2);break;
      }
      cin>>type;
    }
    return 0;
}
//实现distance方法 &重载 
float Point_1D::distance(const Point_1D & p2)
{
      float a;
      a=fabs(x-p2.x);
      cout<<"Distance from Point "<<x<<" to Point "<<p2.x<<" is "<<a<<endl;
      return a;
}
float Point_2D::distance(const Point_2D & p2)
{
      float a;
      a=sqrt((x-p2.x)*(x-p2.x)+(y-p2.y)*(y-p2.y));
      cout<<"Distance from Point("<<x<<","<<y<<") to Point("<<p2.x<<","<<p2.y<<") is "<<a<<endl;
      return a;
}
float Point_3D::distance(const Point_3D & p2)
{
      float a;
      a=sqrt((x-p2.x)*(x-p2.x)+(y-p2.y)*(y-p2.y)+(z-p2.z)*(z-p2.z));
      cout<<"Distance from Point("<<x<<","<<y<<","<<z<<") to Point("<<p2.x<<","<<p2.y<<","<<p2.z<<") is "<<a<<endl;
      return a;
}

 

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谢谢!

posted @ 2017-06-11 17:42  hello_OK  阅读(678)  评论(0编辑  收藏  举报