算法题4——字符串

1、字符串反转

def reverse_string(s):
    return s[::-1]

print(reverse_string('hello word'))

 

2、字符串去重

s = "hello world"
new_s = []
for char in s:
    if char not in new_s:
        new_s.append(char)  # 遍历字符串并加入非重复字符的列表
new_s = "".join(new_s)  # 转换为字符
print(new_s)

 

3、返回第一个重复的字符的下标

s = "hello world"
new_s = []
for char in s:
    if char not in new_s:
        new_s.append(char)  # 遍历字符串并加入非重复字符的列表
    else:
        print(char,s.index(char))
        break