华为机考-简单（2）

 

 1

 

 

 

 

 

 字典的方式

dic = {}
n = int(input()) #没理解
while True:
    try:
        line = input()
        tmp = line.split()
        index = int(tmp[0])
        value = int(tmp[1])
        if index in dic:
            dic[index] += value
        else:
            dic[index] = value
    except:
        break
for k, v in sorted(dic.items()):
    print(k,v) #我的打印方式
    print(f'{k} {v}')

列表与zip函数的使用

while True:
    try:
        n = int(input())
        index, value = [], []
        for i in range(n):
            a, b = list(map(int, input().split()))
            if a in index:
                c = index.index(a)
                value[c] += b
            else:
                index.append(a)
                value.append(b)
        l = list(zip(index, value))
        l.sort()
        for each in l:
            print(each[0], each[1])
    except:
        break

 我喜欢的

while True:
    try:
        n = int(input())
        temp = {}
        for i in range(0, n):
            s = input()
            key = int(s.split(" ")[0])
            value = int(s.split(" ")[1])
            if key not in temp.keys():
                temp[key] = value
            else:
                temp[key] = temp[key] + value
        for key in sorted(temp):
            print(key, temp[key])
    except:
        break

 

 2\

 

 

def count_character(str):
    string = ''.join(set(str))  # 去重后以字符串的形式
    count = 0                   # 开始计数
    for item in string:
        if 0 <= ord(item) <= 127: # ASCII码范围要求
            count += 1         # 计数
    return count

str = input()
print(count_character(str))

def count():
    n=list(input())
    d={}
    for i in n:
        if ord(i)<0 or ord(i)>127:
            continue
        else:
            if d.get(i) is not None:
                pass
            else:
                d[i]=1
    l1=list(d.keys())
    print(len(l1))
count()

print(len(list(filter(lambda x: x if 1 <= ord(x) <= 127 else 0, set(input().replace('\n', ''))))))

3\

 

nums = str(input())  # int-to-string
i = len(nums) - 1
ans = []
while i >= 0:
    ans.append(nums[i])
    i = i - 1

rev = ''.join(ans)  # array-to-string
print(rev)



s = input()
s = reversed(s)
for i in s:
    print(i, end="")

 

4\

while True:
    try:
        nums = input()
        i = len(nums) - 1
        tmp = []
        if 0 <= i <= 1000 and nums.islower() == True:
            tmp.append(nums[i])
            i -= 1
            ans = ''.join(tmp)
            print(ans)
        else:
            print("字符长度大于1000或者字符串含有大写字母")
    except:
        break

 

5\

 

 

while True:
    try:
        s = input().split(' ') #先把句子切分成单词列表
        len_s = len(s)
        for i in range(len_s): #从反方向分别打印列表里的单词
            print(s[len_s-1-i], end = ' ')
        print('')
    except:
        break


while True:
    try:
        line = list(input().split(' '))
        print(' '.join(line[::-1]))
    except:
        break





# 思路：先分解为列表，列表反转后再转字符串
string = input()

if not (1 <= len(string) <= 1000):
    raise Warning

list_string = string.split()

print(" ".join(list_string[::-1]))



while True:
    try:
        want_str = input()
        want_list = want_str.split(" ")
        want_list.reverse()
        res = " ".join(want_list)
        print(res)
    except EOFError:
        break


while True:
    try:
        str1 = str(input())
        str2 = ''
        for i in range(len(str1)-1,-1,-1):
            if(i == len(str1) - 1):
                k2 = len(str1)
                continue
            elif(i == 0):
                str2 += str1[0:k2]
                break
            else:
                if(str1[i] == ' '):
                    str2 = str2 + str1[i+1:k2] + ' '
                    k2 = i

        print(str2)
    except:
        break