多个字符串进行ASCII排序

一、最近做项目需要对多个字符串进行ASCII从小到大排序加密，写个随笔记录下学习，代码如下：

/**
 * 字符串工具类
 * @author skyhcwwu
 */
public class StringUtil {

    public static void main(String[] args) {
        System.err.println("\n---------------------------------------------------------------------------------------------------\n");
        
        String[] source1 = new String[]{"demo", "about", "count", "resolove02", "resolove01", "aboutting", "basic", "abist"};
        System.err.println("排序前String[]:\n" + converToString(source1));
        System.err.println();
        // 排序
        sortString(source1);
        System.err.println("排序后String[]:\n" + converToString(source1));
    }
    
    /**
     * 对传入的字符串数组进行ASCII排序
     * @param source 字符串数组 
     * @return
     */
    public static String[] sortString(String[] source) {
        String str1 = "";
        String str2 = "";
        String temp = "";
        int length = 0;
        for (int i = 0; i < source.length; i++) {
            for (int m = 0; m < source.length - 1; m++) {
                str1 = source[m];
                str2 = source[m + 1];
                length = str1.length() > str2.length() ? str2.length() : str1.length();
                for (int j = 0; j < length; j++) {
                    if (str1.charAt(j) == str2.charAt(j)) {
                        continue;
                    }else if (str1.charAt(j) < str2.charAt(j)) {
                        break;
                    } else {
                        temp = str1;
                        source[m] = str2;
                        source[m + 1] = temp;
                    }
                }
            }

        }
        return source;
    }
    
    public static String converToString(String[] source) {
        StringBuffer sb = new StringBuffer();
        String str1 = "";
        for (int k = 0; k < source.length; k++) {
            str1 = source[k];
            if (k != source.length -1 ) {
                sb.append(str1).append(", ");
            } else {
                sb.append(str1);
            }
        }
        return sb.toString();
    }
    
}

 二、执行main方法后得到的结果：