oracle学习表之sqlserver版 

 1 --建表
 2 create table emp(
 3     empno int primary key,
 4     ename varchar(15) not null,
 5     job varchar(20) not null,
 6     mgr int,
 7     hiredate date,
 8     sal int,
 9     comm int,
10     deptno int);
11 alter table emp add constraint emp_deptno_fk foreign key(deptno) references dept(deptno);
12 --插入数据
13 insert into emp values(7369,'smith','clerk',7902,'1980-12-17',800,null,20);
14 insert into emp values(7499,'allen','salesman',7698,'1981-02-20',1600,300,30);
15 insert into emp values(7521,'ward','salesman',7698,'1981-02-22',1250,500,30);
16 insert into emp values(7566,'jones','manager',7839,'1981-04-02',2975,null,20);
17 insert into emp values(7654,'martin','salesman',7698,'1981-09-28',1250,1400,30);
18 insert into emp values(7698,'blake','manager',7839,'1981-05-01',2850,null,30);
19 insert into emp values(7782,'clark','manager',7839,'1981-06-09',2450,null,10);
20 insert into emp values(7788,'scott','analyst',7566,'1987-04-19',3000,null,20);
21 insert into emp values(7839,'king','president',null,'1981-11-17',5000,null,10);
22 insert into emp values(7844,'turner','salesman',7698,'1981-09-08',1500,0,30);
23 insert into emp values(7876,'adams','clerk',7788,'1987-05-23',1100,null,20);
24 insert into emp values(7900,'james','clerk',7698,'1981-12-03',950,null,30);
25 insert into emp values(7902,'ford','analyst',7566,'1981-12-03',3000,null,20);
26 insert into emp values(7934,'miller','clerk',7782,'1982-01-23',1300,null,10);
 1 --建表
 2 create table dept(
 3     deptno int primary key,
 4     dname varchar(20),
 5     loc varchar(20));
 6 --插入数据
 7 insert into dept values(10,'accounting','new york');
 8 insert into dept values(20,'research','dallas');
 9 insert into dept values(30,'sales','chicago');
10 insert into dept values(40,'operations','boston');
 1 --建表
 2 create table salgrade(
 3     grade int primary key,
 4     losal int,
 5     hisal int);
 6 --插入数据
 7 insert into  salgrade values(1,700,1200);
 8 insert into  salgrade values(2,1201,1400);
 9 insert into  salgrade values(3,1401,2000);
10 insert into  salgrade values(4,2001,3000);
11 insert into  salgrade values(5,3001,9999);

 

posted on 2014-04-07 03:20  confirmBname  阅读(145)  评论(0)  编辑  收藏  举报

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