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[记]在rust中使用xml,xml的序列化与反序列化

在rust中有好几个xml库,但我个人比较推荐的是quick_xml库,这个库的序列化和反序列化使用体验比较好。

启用quick_xml的feature

quick-xml = { version = "0.31.0",features=["serde","serialize"] }
serde = {version="1.0",features=["derive"]}

qucik_mxl的宏体验

依靠强大的宏,quick_xml使用结构体和枚举即可实现xml结构的一一对应。
标签内属性使用宏进行标记
->https://docs.rs/quick-xml/latest/quick_xml/de/

pub struct CalibrationData{
    #[serde(rename = "@xmlns:xsi")]
    xmlns:String,
    CalConfig:Vec<CalConfig>,
}
<CalibrationData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
...
</CalibrationData>
#[derive(Deserialize)]
struct AnyName {
  #[serde(rename = "@one")]
  one: T,

  #[serde(rename = "@two")]
  two: U,
}
<any-tag one="..." two="..."/>
#[derive(Deserialize)]
struct AnyName {
  one: T,
  two: U,
}
<any-tag>
  <one>...</one>
  <two>...</two>
</any-tag>
#[derive(Deserialize)]
struct AnyName {
  #[serde(rename = "@field")]
  attribute: T,
  field: U,
}
<any-tag field="...">
  <field>...</field>
</any-tag>
#[derive(Deserialize)]
struct AnyName {
  #[serde(rename = "@optional")]
  optional: Option<T>,
}
<any-tag optional="..."/><!-- Some("...") -->
<any-tag optional=""/>   <!-- Some("") -->
<any-tag/>               <!-- None -->
#[derive(Deserialize)]
struct AnyName {
  #[serde(default)]
  item: Vec<Item>,
}
<any-tag>
  <item/>
  <item/>
  <item/>
</any-tag>

序列化反序列化

    use serde::Serialize;
    use quick_xml::writer::Writer;
    use quick_xml::se::Serializer;
    use quick_xml::de::from_str;
    use quick_xml::reader::Reader;
        if let Ok(sd) = quick_xml::se::to_string(&sedd){
            println!("sd{}",sd);
        }
let okxml =std::fs::read_to_string("CalDB_NET.xml")?;
let sedd = from_str::<CalibrationData>(&okxml).unwrap();

posted on 2023-12-28 11:31  戳人痛处  阅读(164)  评论(0编辑  收藏  举报