摘要： list1 = [11, [22, 3], [4, ], [55, 66], 8, [9, [7, [12, [34, [26]]]]]] # 去除多余嵌套的列表,得到[11, 22, 3, 4, 55, 66, 8] # 小剥皮 # [11, [22, 3]] # [11, [22, [3, 4] 阅读全文

摘要： https://www.cnblogs.com/liwenzhou/p/8032238.html 阅读全文