题解 AT3909 【Two Arrays】

对于 $\large a_i > b_i$，$\large sum1 += a_i - b_i$

对于 $\large a_i < b_i$，$\large sum1 += \frac{a_i - b_i}{2}$

代码：

#include <iostream>
using namespace std;

int a[10005], b;

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    int n, sum1 = 0, sum2 = 0;
    cin >> n;
    for(register int i = 1; i <= n; i++) cin >> a[i];
    for(register int i = 1; i <= n; i++)
    {
        cin >> b;
        if(a[i] > b) sum1 += a[i] - b;
        else sum2 += (b - a[i]) >> 1;
    }
    cout << (sum1 <= sum2 ? "Yes" : "No") << endl;
    return 0;
}