集合操作的利器:CollectionUtils

使用 CollectionUtils 中四个方法之一执行集合操作.这四种分别是 union(),intersection();disjunction(); subtract();
下列例子就是演示了如何使用上述四个方法处理两个 Collection;
注: 这些方法都是数学的集合算法
import java.util.Arrays;    
import java.util.Collection;    
import java.util.Collections;    
import java.util.List;    
    
import org.apache.commons.collections.CollectionUtils;    
import org.apache.commons.lang.ArrayUtils;    
    
public class CollectionUtilsIntro {  
 @SuppressWarnings("unchecked")    
 public static void main(String[] args) {    
  String[] arrayA = new String[] { "1", "2", "3", "3", "4", "5" };    
  String[] arrayB = new String[] { "3", "4", "4", "5", "6", "7" };    
    
  List<String> a = Arrays.asList(arrayA);    
  List<String> b = Arrays.asList(arrayB);    
  //并集    
  Collection<String> union = CollectionUtils.union(a, b);    
  //交集    
  Collection<String> intersection = CollectionUtils.intersection(a, b);    
  //交集的补集    
  Collection<String> disjunction = CollectionUtils.disjunction(a, b);    
  //集合相减    
  Collection<String> subtract = CollectionUtils.subtract(a, b);    
    
  Collections.sort((List<String>) union);    
  Collections.sort((List<String>) intersection);    
  Collections.sort((List<String>) disjunction);    
  Collections.sort((List<String>) subtract);    
    
  System.out.println("A: " + ArrayUtils.toString(a.toArray()));    
  System.out.println("B: " + ArrayUtils.toString(b.toArray()));    
  System.out.println("--------------------------------------------");    
  System.out.println("Union(A, B): " + ArrayUtils.toString(union.toArray()));    
  System.out.println("Intersection(A, B): " + ArrayUtils.toString(intersection.toArray()));    
  System.out.println("Disjunction(A, B): " + ArrayUtils.toString(disjunction.toArray()));    
  System.out.println("Subtract(A, B): " + ArrayUtils.toString(subtract.toArray()));    
 }    
} 
 
输出如下:
A: {1,2,3,3,4,5}
B: {3,4,4,5,6,7}
--------------------------------------------
Union(A, B): {1,2,3,3,4,4,5,6,7}
Intersection(A, B): {3,4,5}
Disjunction(A, B): {1,2,3,4,6,7}
Subtract(A, B): {1,2,3}

posted on 2011-07-01 11:07  GongTao  阅读(9274)  评论(0编辑  收藏  举报

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