Leetcode 668. Kth Smallest Number in Multiplication Table
Problem:
Nearly every one have used the Multiplication Table. But could you find out the k-th
smallest number quickly from the multiplication table?
Given the height m
and the length n
of a m * n
Multiplication Table, and a positive integer k
, you need to return the k-th
smallest number in this table.
Example 1:
Input: m = 3, n = 3, k = 5 Output: Explanation: The Multiplication Table: 1 2 3 2 4 6 3 6 9 The 5-th smallest number is 3 (1, 2, 2, 3, 3).
Example 2:
Input: m = 2, n = 3, k = 6 Output: Explanation: The Multiplication Table: 1 2 3 2 4 6 The 6-th smallest number is 6 (1, 2, 2, 3, 4, 6).
Note:
- The
m
andn
will be in the range [1, 30000]. - The
k
will be in the range [1, m * n]
Solution:
特殊二分法的典型,难点在于是否能看出用二分法解决这道题,原理很简单,就是在1到m*n之间寻找一个数pivot,计算小于它的数的数量,与k做比较不断缩小搜索范围。
Code:
1 class Solution { 2 public: 3 int findKthNumber(int m, int n, int k) { 4 int left = 1; 5 int right = m*n; 6 while(left < right){ 7 int pivot = left+(right-left)/2; 8 int count = 0; 9 for(int i = 1;i <= m;++i) 10 count += (pivot > i*n) ? n : (pivot/i); 11 if(count < k) 12 left = pivot+1; 13 else 14 right = pivot; 15 } 16 return left; 17 } 18 };