C# 使用表达式树获取特性的值
一、定义特性
/// <summary> /// 定义特性 /// </summary> [AttributeUsage(AttributeTargets.Field | AttributeTargets.Class | AttributeTargets.Property, AllowMultiple = false)] public class DataMember : Attribute { public string Name { get; set; } public string Type { get; set; } }
二、创建工具类
利用泛型类得知要获取那个类上成员特性的类型,这样就能用Lambda表达式了。Expression.Body读取时是 System.Linq.Expressions.PropertyExpression 类型,找不到断点中Member属性。所以需要转换成 System.Linq.Expressions.MemberExpression 类型
/// <summary> /// 获取特性工具类 /// </summary> /// <typeparam name="T"></typeparam> public static class AttrTool<T> { /// <summary> /// 获取特性Name属性 /// </summary> /// <typeparam name="Result"></typeparam> /// <param name="expression"></param> /// <returns></returns> public static string DataMemberName<Result>(Expression<Func<T, Result>> expression) { var body = expression.Body as MemberExpression; var attr = body.Member.CustomAttributes.FirstOrDefault(t => t.AttributeType == typeof(DataMember)); var property = attr.NamedArguments.FirstOrDefault(t => t.MemberName == "Name"); return property.TypedValue.Value.ToString(); } /// <summary> /// 获取特性Type属性 /// </summary> /// <typeparam name="Result"></typeparam> /// <param name="expression"></param> /// <returns></returns> public static string DataMemberType<Result>(Expression<Func<T, Result>> expression) { var body = expression.Body as MemberExpression; var attr = body.Member.CustomAttributes.FirstOrDefault(t => t.AttributeType == typeof(DataMember)); var property = attr.NamedArguments.FirstOrDefault(t => t.MemberName == "Type"); return property.TypedValue.Value.ToString(); } }
三、定义测试模型及调用
class Program { static void Main(string[] args) { var temp = AttrTool<AttrModel>.DataMemberName(t => t.Name); Console.WriteLine(); } } /// <summary> /// 测试模型 /// </summary> public class AttrModel { [DataMember(Name = "this is Test", Type = "string")] public string Name { get; set; } }