去哪儿网2015校招研发类笔试题
从网上找到的题目,自己做了一遍
1、二分查找
2、给定一个字符串,得到这个字符串中首先出现两次的那个字符
方法:可以用一个hash_map或者数组来存储字符出现的次数,一旦有一个出现了2次,就返回该字符
3、尝试在以下文本中搜索并打印出包含单词"your"(不区分大小写)的句子,并按照出现次数从高到低排序
Make yourself at home
None of your business
I will be more careful
How about going to a move?
Your life is your own affair
方法:统计每行中your出现的次数,然后 进行排序
代码:
1 #include<iostream> 2 #include<hash_map> 3 #include<vector> 4 #include<string> 5 #include<sstream> 6 #include<algorithm> 7 using std::vector; 8 using std::string; 9 using std::cout; 10 using std::cin; 11 using std::endl; 12 using std::hash_map; 13 using std::istringstream; 14 //题目1:二分查找 15 int bin_search(int num[], int start, int end, int n); 16 int bin_search(int num[],int length,int n) 17 { 18 if (num==0||length<=0) 19 { 20 return false; 21 } 22 23 return bin_search(num, 0, length - 1, n); 24 } 25 26 int bin_search(int num[],int start,int end,int n) 27 { 28 if (num==NULL||start<0||end<start||end<0) 29 { 30 throw std::exception("Invalid input"); 31 } 32 33 if (start==end) 34 { 35 if (num[start] == n) 36 { 37 return start; 38 } 39 else 40 return -1; 41 } 42 43 int mid = start + (end - start) / 2; 44 if (num[mid]==n) 45 { 46 return mid; 47 } 48 else if (num[mid]<n) 49 { 50 return bin_search(num, mid + 1, end, n); 51 } 52 else 53 { 54 return bin_search(num, start, mid - 1, n); 55 } 56 } 57 58 //题目2:字符串中第一次出现2次的字符 59 60 char occur2times(char* ch) 61 { 62 char word = '\0'; 63 if (ch==NULL) 64 { 65 return word; 66 } 67 68 std::size_t length = strlen(ch); 69 std::hash_map<char, int> hashmap; 70 for (int i = 0; i < length;++i) 71 { 72 std::hash_map<char, int>::const_iterator itr= hashmap.find(ch[i]); 73 if (itr==hashmap.cend()) 74 { 75 hashmap.insert(std::make_pair(ch[i], 1)); 76 } 77 else 78 { 79 word = itr->first; 80 break; 81 } 82 } 83 84 return word; 85 } 86 87 /*题目3: 88 尝试在以下文本中搜索并打印出包含单词"your"(不区分大小写)的句子,并按照出现次数从高到低排序 89 Make yourself at home 90 None of your business 91 I will be more careful 92 How about going to a move? 93 Your life is your own affair 94 */ 95 bool cmpValue(const std::pair<int, int>& lhs, const std::pair<int, int>& rhs) 96 { 97 return lhs.second > rhs.second; 98 } 99 100 void SentenceYour(const std::vector<string>& inputstr, std::vector<int>& output) 101 { 102 if (inputstr.empty()) 103 { 104 return; 105 } 106 107 108 //int *count = new int[inputstr.size()]; 109 //memset(count, 0, sizeof(int)*inputstr.size()); 110 111 hash_map<int, int> count; 112 for (vector<string>::size_type line_num = 0; line_num != inputstr.size(); ++line_num) 113 { 114 istringstream line(inputstr[line_num]); 115 string word; 116 while (line>>word) 117 { 118 std::transform(word.begin(), word.end(), word.begin(), ::tolower); 119 if (word=="your") 120 { 121 ++count[line_num]; 122 } 123 } 124 } 125 126 vector<std::pair<int, int>> counts(count.begin(),count.end()); 127 128 std::sort(counts.begin(), counts.end(), cmpValue); 129 for (vector<std::pair<int, int>>::const_iterator citr = counts.cbegin(); citr != counts.cend();++citr) 130 { 131 if (citr->second!=0) 132 { 133 output.push_back(citr->first); 134 } 135 } 136 } 137 int main() 138 { 139 140 //题目1: 141 int num[] = { 1, 2, 3, 4, 5, 6, 7, 8 }; 142 int n = 0; 143 int pos = bin_search(num, 8, n); 144 if (pos!=-1) 145 { 146 std::cout << n << "has found at " <<pos<< std::endl; 147 } 148 else 149 { 150 std::cout << n << "has not found" << std::endl; 151 } 152 153 //题目2 154 char ch[] = "abcdedab"; 155 char a = occur2times(ch); 156 if (a!='\0') 157 { 158 std::cout << "first char occured 2 times is " << a << std::endl; 159 } 160 else 161 { 162 std::cout << "no char occured 2 times " << std::endl; 163 164 } 165 166 167 //题目3: 168 vector<string> input; 169 cout << "输入文本\n"; 170 string line; 171 while(getline(cin,line)) 172 { 173 input.push_back(line); 174 } 175 vector<int> output; 176 SentenceYour(input, output); 177 if (!output.empty()) 178 { 179 cout << "sentence have your are:\n"; 180 vector<int>::const_iterator itr = output.begin(); 181 while (itr!=output.end()) 182 { 183 cout << input[*itr++] << endl; 184 } 185 } 186 else 187 { 188 cout << "no sentence have your\n"; 189 190 } 191 return 0; 192 }
输出:
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