十进制转换

# bin2dec
# 二进制 to 十进e5a48de588b662616964757a686964616f31333335336437制: int(str,n=10) 
def bin2dec(string_num):
    return str(int(string_num, 2))
 
# hex2dec
# 十六进制 to 十进制
def hex2dec(string_num):
    return str(int(string_num.upper(), 16))
 
# dec2bin
# 十进制 to 二进制: bin() 
def dec2bin(string_num):
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num,rem = divmod(num, 2)
        mid.append(base[rem])
 
    return ''.join([str(x) for x in mid[::-1]])
 
# dec2hex
# 十进制 to 八进制: oct() 
# 十进制 to 十六进制: hex() 
def dec2hex(string_num):
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num,rem = divmod(num, 16)
        mid.append(base[rem])
 
    return ''.join([str(x) for x in mid[::-1]])

base = [str(x) for x in range(10)] + [chr(x) for x in range(ord('A'), ord('A') + 6)]

def dec2bin(string_num):
    '''十进制转换为 二进制'''
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num, rem = divmod(num, 2)
        mid.append(base[rem])

    return ''.join([str(x) for x in mid[::-1]])

def dec2oct(string_num):
    '''转换为 八进制'''
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num, rem = divmod(num, 8)
        mid.append(base[rem])

    return ''.join([str(x) for x in mid[::-1]])


def dec2hex(string_num):
    '''转换为 十六进制'''
    num = int(string_num)
    mid = []
    while True:
        if num == 0: break
        num, rem = divmod(num, 16)
        mid.append(base[rem])

    return ''.join([str(x) for x in mid[::-1]])



num = float(input())

print(dec2bin(num),dec2oct(num),dec2hex(num))

2020-06-02

posted @ 2020-06-02 14:00  CodeYaSuo  阅读(210)  评论(0编辑  收藏  举报