函数式回文串
def all_equal(lst):
print(lst[:])
# [1, 2, 3, 4, 5, 6]
# [1, 1, 1, 1]
print(lst[::-1])
# [6, 5, 4, 3, 2, 1]
# [1, 1, 1, 1]
print(lst[1:] == lst[:-1])
all_equal([1, 2, 3, 4, 5, 6])
# False
all_equal([1, 1, 1, 1])
# True
2020-05-03
本文来自博客园,作者:CodeYaSuo,转载请注明原文链接:https://www.cnblogs.com/hany-postq473111315/p/12821617.html