MySQL中建立Oracle中SCOTT数据示例

1、创建 scott 数据库

CREATE DATABASE scott;

2、创建 scott 数据库中的 dept 表

CREATE TABLE dept(
    deptno      INT UNSIGNED PRIMARY KEY COMMENT '部门编号',
    dname       VARCHAR(15) COMMENT '部门名称',
    loc         VARCHAR(50) COMMENT '部门所在位置'
) COMMENT='部门表';

插入数据库 scott 中表 dept 的初始化数据

INSERT INTO dept VALUES (10,'ACCOUNTING','NEW YORK');
INSERT INTO dept VALUES (20,'RESEARCH','DALLAS');
INSERT INTO dept VALUES (30,'SALES','CHICAGO');
INSERT INTO dept VALUES (40,'OPERATIONS','BOSTON');

3、创建 scott 数据库中的 emp 表

CREATE TABLE emp(
    empno           INT UNSIGNED AUTO_INCREMENT PRIMARY KEY COMMENT '雇员编号',
    ename           VARCHAR(15) COMMENT '雇员姓名',
    job             VARCHAR(10) COMMENT '雇员职位',
    mgr             INT UNSIGNED COMMENT '雇员对应的领导的编号',
    hiredate        DATE COMMENT '雇员的雇佣日期',
    sal             DECIMAL(7,2) COMMENT '雇员的基本工资',
    comm            DECIMAL(7,2) COMMENT '奖金',
    deptno          INT UNSIGNED COMMENT '所在部门',
    FOREIGN KEY(deptno) REFERENCES dept(deptno)
) COMMENT='雇员表';

插入数据库 scott 中表 emp 的初始数据

INSERT INTO emp VALUES    (7369,'SMITH','CLERK',7902,'1980-12-17',800,NULL,20);
INSERT INTO emp VALUES    (7499,'ALLEN','SALESMAN',7698,'1981-2-20',1600,300,30);
INSERT INTO emp VALUES    (7521,'WARD','SALESMAN',7698,'1981-2-22',1250,500,30);
INSERT INTO emp VALUES    (7566,'JONES','MANAGER',7839,'1981-4-2',2975,NULL,20);
INSERT INTO emp VALUES    (7654,'MARTIN','SALESMAN',7698,'1981-9-28',1250,1400,30);
INSERT INTO emp VALUES    (7698,'BLAKE','MANAGER',7839,'1981-5-1',2850,NULL,30);
INSERT INTO emp VALUES    (7782,'CLARK','MANAGER',7839,'1981-6-9',2450,NULL,10);
INSERT INTO emp VALUES    (7788,'SCOTT','ANALYST',7566,'87-7-13',3000,NULL,20);
INSERT INTO emp VALUES    (7839,'KING','PRESIDENT',NULL,'1981-11-17',5000,NULL,10);
INSERT INTO emp VALUES    (7844,'TURNER','SALESMAN',7698,'1981-9-8',1500,0,30);
INSERT INTO emp VALUES    (7876,'ADAMS','CLERK',7788,'87-7-13',1100,NULL,20);
INSERT INTO emp VALUES    (7900,'JAMES','CLERK',7698,'1981-12-3',950,NULL,30);
INSERT INTO emp VALUES    (7902,'FORD','ANALYST',7566,'1981-12-3',3000,NULL,20);

4、创建数据库 scott 中的 salgrade 表，工资等级表

CREATE TABLE salgrade(
    grade       INT UNSIGNED COMMENT '工资等级',
    losal       INT UNSIGNED COMMENT '此等级的最低工资',
    hisal       INT UNSIGNED COMMENT '此等级的最高工资'  
) COMMENT='工资等级表';

插入数据库 scott 中表 salgrade 的初始数据

INSERT INTO salgrade VALUES (1,700,1200);
INSERT INTO salgrade VALUES (2,1201,1400);
INSERT INTO salgrade VALUES (3,1401,2000);
INSERT INTO salgrade VALUES (4,2001,3000);
INSERT INTO salgrade VALUES (5,3001,9999);

5、创建数据库 scott 的 bonus 表，工资表

CREATE TABLE bonus(
    ename       VARCHAR(10) COMMENT '雇员姓名',
    job         VARCHAR(9) COMMENT '雇员职位',
    sal         DECIMAL(7,2) COMMENT '雇员工资',
    comm        DECIMAL(7,2) COMMENT '雇员资金'  
) COMMENT='工资表';

 附：经典查询练手 https://www.cnblogs.com/huyong/archive/2011/06/03/2071228.html