Python | 排列与组合

阅读目录

• 示例
• 不考虑顺序
• 考虑顺序
• 列表之间的组合

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示例

以下面的列表为例，

import itertools
L = [1, 2, 3, 4]

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不考虑顺序

comb1 = list(itertools.combinations([1,2,3,4],1))
'''
[(1,), (2,), (3,), (4,)]
'''
 
comb2 = list(itertools.combinations([1,2,3,4],2))
'''
[(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)]
'''
 
comb3 = list(itertools.combinations([1,2,3,4],3))
'''
[(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
'''
 

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考虑顺序

comb1 = list(itertools.permutations([1,2,3,4],1))
'''
[(1,), (2,), (3,), (4,)]
'''
 
comb2 = list(itertools.permutations([1,2,3,4],2))
'''
[(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)]
'''
 
comb3 = list(itertools.permutations([1,2,3,4],3))
'''
[(1, 2, 3), (1, 2, 4), (1, 3, 2), (1, 3, 4), (1, 4, 2), (1, 4, 3), (2, 1, 3), (2, 1, 4), (2, 3, 1), (2, 3, 4), (2, 4, 1), (2, 4, 3), (3, 1, 2), (3, 1, 4), (3, 2, 1), (3, 2, 4), (3, 4, 1), (3, 4, 2), (4, 1, 2), (4, 1, 3), (4, 2, 1), (4, 2, 3), (4, 3, 1), (4, 3, 2)]
'''
 
 

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列表之间的组合

import itertools
 
list1 = [1, 2, 3, 4]
list2 = [5, 6, 7, 8,9]
print(list(itertools.product(list1, list2)))
 
# [(1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9), (3, 5), (3, 6), (3, 7), (3, 8), (3, 9), (4, 5), (4, 6), (4, 7), (4, 8), (4, 9)]
 

https://blog.csdn.net/MissMango0820/article/details/127958117