摘要: Dark roadsTime Limit : 2000/1000ms (Java/Other)Memory Limit : 32768/32768K (Java/Other)Total Submission(s) : 7Accepted Submission(s) : 2Problem Descri... 阅读全文
posted @ 2015-08-12 21:37 handsomecui 阅读(348) 评论(0) 推荐(0) 编辑
摘要: Fibonacci Tree Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3006 Accepted Submission(s): 966 P 阅读全文
posted @ 2015-08-12 21:26 handsomecui 阅读(1018) 评论(0) 推荐(0) 编辑
摘要: TreeTime Limit : 6000/2000ms (Java/Other)Memory Limit : 32768/32768K (Java/Other)Total Submission(s) : 2Accepted Submission(s) : 2Problem DescriptionT... 阅读全文
posted @ 2015-08-12 19:03 handsomecui 阅读(432) 评论(0) 推荐(0) 编辑
摘要: Connect the CitiesTime Limit : 2000/1000ms (Java/Other)Memory Limit : 32768/32768K (Java/Other)Total Submission(s) : 4Accepted Submission(s) : 3Proble... 阅读全文
posted @ 2015-08-12 18:57 handsomecui 阅读(372) 评论(0) 推荐(0) 编辑
摘要: Ice_cream’s world IIITime Limit : 3000/1000ms (Java/Other)Memory Limit : 32768/32768K (Java/Other)Total Submission(s) : 6Accepted Submission(s) : 3Pro... 阅读全文
posted @ 2015-08-12 18:54 handsomecui 阅读(359) 评论(0) 推荐(0) 编辑
摘要: 首先要知道memset函数是对字节为单位进行赋值的;void *memset(void *s, int ch,size_tn);函数解释:将s中前n个字节 (typedef unsigned int size_t )用 ch 替换并返回 s 。其实这里面的ch就是ascii为ch的字符;将s所指向的... 阅读全文
posted @ 2015-08-12 13:02 handsomecui 阅读(22538) 评论(1) 推荐(2) 编辑