python 基础 set 集合类型补充

 

    为啥今天又重提这个数据类型呢?平时用的少,等要用起来的时候才发现,自己对这块啥都不知道了,so,今天就把这块再梳理一下咯。

一、set集合,是一个无序且不重复的元素集合。这一点是非常重要的。

二、集合中的方法介绍:

  1 class set(object):
  2     """
  3     set() -> new empty set object
  4     set(iterable) -> new set object
  5      
  6     Build an unordered collection of unique elements.
  7     """
  8     def add(self, *args, **kwargs): # real signature unknown
  9         """
 10         Add an element to a set,添加元素
 11          
 12         This has no effect if the element is already present.
 13         """
 14         pass
 15  
 16     def clear(self, *args, **kwargs): # real signature unknown
 17         """ Remove all elements from this set. 清除内容"""
 18         pass
 19  
 20     def copy(self, *args, **kwargs): # real signature unknown
 21         """ Return a shallow copy of a set. 浅拷贝  """
 22         pass
 23  
 24     def difference(self, *args, **kwargs): # real signature unknown
 25         """
 26         Return the difference of two or more sets as a new set. A中存在,B中不存在
 27          
 28         (i.e. all elements that are in this set but not the others.)
 29         """
 30         pass
 31  
 32     def difference_update(self, *args, **kwargs): # real signature unknown
 33         """ Remove all elements of another set from this set.  从当前集合中删除和B中相同的元素"""
 34         pass
 35  
 36     def discard(self, *args, **kwargs): # real signature unknown
 37         """
 38         Remove an element from a set if it is a member.
 39          
 40         If the element is not a member, do nothing. 移除指定元素,不存在不保错
 41         """
 42         pass
 43  
 44     def intersection(self, *args, **kwargs): # real signature unknown
 45         """
 46         Return the intersection of two sets as a new set. 交集
 47          
 48         (i.e. all elements that are in both sets.)
 49         """
 50         pass
 51  
 52     def intersection_update(self, *args, **kwargs): # real signature unknown
 53         """ Update a set with the intersection of itself and another.  取交集并更更新到A中 """
 54         pass
 55  
 56     def isdisjoint(self, *args, **kwargs): # real signature unknown
 57         """ Return True if two sets have a null intersection.  如果没有交集,返回True,否则返回False"""
 58         pass
 59  
 60     def issubset(self, *args, **kwargs): # real signature unknown
 61         """ Report whether another set contains this set.  是否是子序列"""
 62         pass
 63  
 64     def issuperset(self, *args, **kwargs): # real signature unknown
 65         """ Report whether this set contains another set. 是否是父序列"""
 66         pass
 67  
 68     def pop(self, *args, **kwargs): # real signature unknown
 69         """
 70         Remove and return an arbitrary set element.
 71         Raises KeyError if the set is empty. 移除元素
 72         """
 73         pass
 74  
 75     def remove(self, *args, **kwargs): # real signature unknown
 76         """
 77         Remove an element from a set; it must be a member.
 78          
 79         If the element is not a member, raise a KeyError. 移除指定元素,不存在保错
 80         """
 81         pass
 82  
 83     def symmetric_difference(self, *args, **kwargs): # real signature unknown
 84         """
 85         Return the symmetric difference of two sets as a new set.  对称差集
 86          
 87         (i.e. all elements that are in exactly one of the sets.)
 88         """
 89         pass
 90  
 91     def symmetric_difference_update(self, *args, **kwargs): # real signature unknown
 92         """ Update a set with the symmetric difference of itself and another. 对称差集,并更新到a中 """
 93         pass
 94  
 95     def union(self, *args, **kwargs): # real signature unknown
 96         """
 97         Return the union of sets as a new set.  并集
 98          
 99         (i.e. all elements that are in either set.)
100         """
101         pass
102  
103     def update(self, *args, **kwargs): # real signature unknown
104         """ Update a set with the union of itself and others. 更新 """
105         pass
集合方法摘录

三、常用方法举例:

 1 linux = set(['alex','jack','rain','sb'])
 2 python = set(['sb','alex','mack','rachel'])
 3 
 4 #集合linux与集合python 中都有的(交集)
 5 a = linux.intersection(python)
 6 print(a) # {'sb', 'alex'}
 7 
 8 # 求差集 linux 中有而python中没有的
 9 b = linux.difference(python)
10 print(b) # {'rain', 'jack'}

    集合部分的简单操作也就这些内容了。

posted @ 2017-07-07 17:06  还是牛  阅读(207)  评论(0编辑  收藏  举报