C# 判断当前时间是否为工作时间



 

　　前段时间做项目时遇到判断当前时间是否为工作时间的需求，我认为比较有意思，所以拿出来与大家分享，一同学习。

注：　

1._strWorkingDayAM等值，这里赋默认值，通常情况下应读配置文件。

2.clsArrayList类是将字符串截取为数组的功能类，在我的博客中有写，有兴趣的朋友可以看一下。

        private string _strWorkingDayAM="08:00";//工作时间上午08:00
        private string _strWorkingDayPM = "16:00";
        private string _strRestDay="6,7";//周几休息日 周六周日为 6,7

        private TimeSpan dspWorkingDayAM;//工作时间上午08:00
        private TimeSpan dspWorkingDayPM;
        clsArrayList myArrayList;
        
        private bool m_IsWorkingDay()
        {
            string strWeekNow = this.m_GetWeekNow();//当前周几
            //判断是否有休息日
            for (int i = 0; i < myArrayList.p_Count; i++)
            {
                if (strWeekNow == myArrayList.m_GetItem(i))
                {
                    return false;
                }
            }
            //判断当前时间是否在工作时间段内
            TimeSpan dspNow = DateTime.Now.TimeOfDay;
            if (dspNow > dspWorkingDayAM && dspNow < dspWorkingDayPM)
            {
                return true;
            }
            return false;
        }
        //初始化默认值
        private void m_InitWorkingDay()
        {
            dspWorkingDayAM = DateTime.Parse(_strWorkingDayAM).TimeOfDay;
            dspWorkingDayPM = DateTime.Parse(_strWorkingDayPM).TimeOfDay;
            myArrayList = new myClass.clsArrayList(_strRestDay, ',');
        }
        //调用
        void Button1Click(object sender, EventArgs e)
        {
            this.m_InitWorkingDay();

            bool bol = this.m_IsWorkingDay();

            MessageBox.Show(bol.ToString());

        }
　　　　 //获取当前周几

        private string m_GetWeekNow()
        {
            string strWeek = DateTime.Now.DayOfWeek.ToString();
            switch (strWeek)
            { 
                case "Monday" :
                    return "1";
                case "Tuesday":
                    return "2";
                case "Wednesday":
                    return "3";
                case "Thursday":
                    return "4";
                case "Friday":
                    return "5";
                case "Saturday":
                    return "6";
                case "Sunday":
                    return "7";
            }
            return "0";
        }